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Question
Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.
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Solution
\[\ce{Ni}\] (28): 1s2 2s2 2p6 3s2 3p6 3d8 4s2
\[\ce{Ni^{2+}}\] (26): 1s2 2s2 2p6 3s2 3p6 3d8
Hence, to form \[\ce{Ni^{2+}}\] ion, it will lose 2 electrons from 4s orbital.
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