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Question
Draw shapes of 2s orbitals.
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Solution

Shapes of 1s and 2s orbitals Boundary surface diagrams
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| (i) | (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2` |
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(iii) Magnetic quantum number determines the size of the orbital.
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The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
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| (ii) \[\ce{Cu^{2+}}\] | (b) 1s2 2s2 2p6 3s2 3p6 3d10 4s2 |
| (iii) \[\ce{Zn^{2+}}\] | (c) 1s2 2s2 2p6 3s2 3p6 3d10 4s1 |
| (iv) \[\ce{Cr^{3+}}\] | (d) 1s2 2s2 2p6 3s2 3p6 3d9 |
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| (ii) Electron | (b) Probability density |
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