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The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of - Chemistry

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Question

The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

1s, 2s, 3s, 2p

Short/Brief Note
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Solution

Orbitals s p d f
l 0 1 2 3

 

Orbitals n n + l
1s 1 1
2s 2 2
3s 3 3
2p 2 3

Thus the increasing order of energy is 1s < 2s < 2p < 3s

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Chapter 2: Structure of Atom - Multiple Choice Questions (Type - I) [Page 19]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 27.(i).(a) | Page 19

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