Advertisements
Advertisements
Question
Calculate the total number of angular nodes and radial nodes present in 3p orbital.
Advertisements
Solution
The number of radial nodes is given by n – l – 1, where n is the principal quantum number, l is the azimuthal quantum number.
The number of angular nodes is given by n – l, where n is the principal quantum number, l is the azimuthal quantum number.
Here n = 3 and l = 1
Thus, angular nodes = 3 – 1 = 2 and radial node = 3 – 1 – 1 = 1.
APPEARS IN
RELATED QUESTIONS
Using s, p, d notations, describe the orbital with the following quantum numbers n = 3; l =1.
Give the names of quantum numbers.
State and explain Pauli’s exclusion principle.
Write electronic configurations of \[\ce{Fe, Fe2+, Fe3+}\].
Write condensed orbital notation of electronic configuration of the following element:
Carbon (Z = 6)
Write condensed orbital notation of electronic configuration of the following element:
Oxygen (Z = 8)
Write condensed orbital notation of electronic configuration of the following element:
Silicon (Z = 14)
Write condensed orbital notation of electronic configuration of the following element:
Chlorine (Z = 17)
Draw shapes of 2s orbitals.
Draw shapes of 2p orbitals.
Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).
Indicate the number of unpaired electron in:
Cr (Z = 24)
Which of the following properties of atom could be explained correctly by Thomson Model of atom?
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, arrange the following orbitals in the increasing order of energy.
5p, 4d, 5d, 4f, 6s
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, arrange the following orbitals in the increasing order of energy.
5f, 6d, 7s, 7p
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
5p, 5d, 5f, 6s, 6p
Match the quantum numbers with the information provided by these.
| Quantum number | Information provided |
| (i) Principal quantum number | (a) orientation of the orbital |
| (ii) Azimuthal quantum number | (b) energy and size of orbital |
| (iii) Magnetic quantum number | (c) spin of electron |
| (iv) Spin quantum number | (d) shape of the orbital |
Match species given in Column I with the electronic configuration given in Column II.
| Column I | Column II |
| (i) \[\ce{Cr}\] | (a) [Ar]3d84s0 |
| (ii) \[\ce{Fe^{2+}}\] | (b) [Ar]3d104s1 |
| (iii) \[\ce{Ni^{2+}}\] | (c) [Ar]3d64s0 |
| (iv) \[\ce{Cu}\] | (d) [Ar] 3d54s1 |
| (e) [Ar]3d64s2 |
In the case of R, S configuration the group having the highest priority is ______.
