हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Calculate the total number of angular nodes and radial nodes present in 3p orbital.

Advertisements
Advertisements

प्रश्न

Calculate the total number of angular nodes and radial nodes present in 3p orbital.

संख्यात्मक
Advertisements

उत्तर

The number of radial nodes is given by n – l – 1, where n is the principal quantum number, l is the azimuthal quantum number.

The number of angular nodes is given by n – l, where n is the principal quantum number, l is the azimuthal quantum number.

Here n = 3 and l = 1 

Thus, angular nodes = 3 – 1 = 2 and radial node = 3 – 1 – 1 = 1.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ १९]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 26 | पृष्ठ १९

संबंधित प्रश्न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


State Heisenberg uncertainty principle.


Explain the anomalous behaviour of copper.


Explain the anomalous behaviour of chromium.


Write condensed orbital notation of electronic configuration of the following element:

Oxygen (Z = 8)


Write condensed orbital notation of electronic configuration of the following element:

Silicon (Z = 14)


Which mineral among the following contains vanadium in it?


Number of angular nodes for 4d orbital is ______.


Orbital angular momentum depends on ______.


Which of the following statements concerning the quantum numbers are correct?

(i) Angular quantum number determines the three dimensional shape of the orbital.

(ii) The principal quantum number determines the orientation and energy of the orbital.

(iii) Magnetic quantum number determines the size of the orbital.

(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


Match the following species with their corresponding ground state electronic configuration.

Atom / Ion Electronic configuration
(i) \[\ce{Cu}\] (a) 1s2 2s2 2p6 3s2 3p6 3d10
(ii) \[\ce{Cu^{2+}}\] (b) 1s2 2s2 2p6 3s2 3p6 3d10 4s2
(iii) \[\ce{Zn^{2+}}\] (c) 1s2 2s2 2p6 3s2 3p6 3d10 4s1
(iv) \[\ce{Cr^{3+}}\] (d) 1s2 2s2 2p6 3s2 3p6 3d9
  (e) 1s2 2s2 2p6 3s2 3p6 3d3

Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2

Choose the INCORRECT statement


Which of the following is the correct plot for the probability density ψ2 (r) as a function of distance 'r' of the electron from the nucleus for 2s orbitals?


Which of the following is not the permissible arrangement of electrons in an atom?


What are the possible values of magnetic quantum number for p orbital?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×