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प्रश्न
Match the following species with their corresponding ground state electronic configuration.
| Atom / Ion | Electronic configuration |
| (i) \[\ce{Cu}\] | (a) 1s2 2s2 2p6 3s2 3p6 3d10 |
| (ii) \[\ce{Cu^{2+}}\] | (b) 1s2 2s2 2p6 3s2 3p6 3d10 4s2 |
| (iii) \[\ce{Zn^{2+}}\] | (c) 1s2 2s2 2p6 3s2 3p6 3d10 4s1 |
| (iv) \[\ce{Cr^{3+}}\] | (d) 1s2 2s2 2p6 3s2 3p6 3d9 |
| (e) 1s2 2s2 2p6 3s2 3p6 3d3 |
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उत्तर
| Atom / Ion | Electronic configuration |
| (i) \[\ce{Cu}\] | (c) 1s2 2s2 2p6 3s2 3p6 3d10 4s1 |
| (ii) \[\ce{Cu^{2+}}\] | (d) 1s2 2s2 2p6 3s2 3p6 3d9 |
| (iii) \[\ce{Zn^{2+}}\] | (a) 1s2 2s2 2p6 3s2 3p6 3d10 |
| (iv) \[\ce{Cr^{3+}}\] | (e) 1s2 2s2 2p6 3s2 3p6 3d3 |
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संबंधित प्रश्न
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Number of angular nodes for 4d orbital is ______.
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5f, 6d, 7s, 7p
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
4d, 4f, 5s, 5p
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Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
5p, 5d, 5f, 6s, 6p
Match the following
| (i) Photon | (a) Value is 4 for N shell |
| (ii) Electron | (b) Probability density |
| (iii) ψ2 | (c) Always positive value |
| (iv) Principal quantum number n | (d) Exhibits both momentum and wavelength |
What are the possible values of magnetic quantum number for p orbital?
