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Which of the following options does not represent ground state electronic configuration of an atom? - Chemistry

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प्रश्न

Which of the following options does not represent ground state electronic configuration of an atom?

पर्याय

  • 1s2 2s2 2p6 3s2 3p6 3d8 4s2

  • 1s2 2s2 2p6 3s2 3p6 3d9 4s2

  • 1s2 2s2 2p6 3s2 3p6 3d10 4s1

  • 1s2 2s2 2p6 3s2 3p6 3d5 4s1

MCQ
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उत्तर

1s2 2s2 2p6 3s2 3p6 3d9 4s

Explanation:

As per Hund’s rule the half-filled and fully filled orbital leads to extra stability due to the symmetry thus fully filled 3d and half-filled 4s is preferred.

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पाठ 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ १४]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 2 | पृष्ठ १४

संबंधित प्रश्‍न

Explain the anomalous behaviour of chromium.


Write electronic configurations of \[\ce{Fe, Fe2+, Fe3+}\].


Write condensed orbital notation of electronic configuration of the following element:

Carbon (Z = 6)


Write condensed orbital notation of electronic configuration of the following element:

Chlorine (Z = 17)


Explain in brief, the significance of the azimuthal quantum number.


Using the concept of quantum numbers, calculate the maximum numbers of electrons present in the ‘M’ shell. Give their distribution in shells, subshells, and orbitals.


Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).


Indicate the number of unpaired electron in:

Cr (Z = 24)


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

In which of the following pairs, the ions are iso-electronic?

(i) \[\ce{Na^{+}, Mg^{2+}}\]

(ii) \[\ce{Al3^{+}, O-}\]

(iii) \[\ce{Na+ , O2-}\]

(iv) \[\ce{N3-, Cl-}\]


Which of the following statements concerning the quantum numbers are correct?

(i) Angular quantum number determines the three dimensional shape of the orbital.

(ii) The principal quantum number determines the orientation and energy of the orbital.

(iii) Magnetic quantum number determines the size of the orbital.

(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

4s, 3s, 3p, 4d


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5p, 4d, 5d, 4f, 6s


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5f, 6d, 7s, 7p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

4d, 4f, 5s, 5p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2

Which of the following is the correct plot for the probability density ψ2 (r) as a function of distance 'r' of the electron from the nucleus for 2s orbitals?


Which one of the following laws will represent the pairing of electrons in a subshell after each orbital is filled with one electron?


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