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The pair of ions having same electronic configuration is ______.

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प्रश्न

The pair of ions having same electronic configuration is ______.

पर्याय

  • \[\ce{Cr^{3+}, Fe^{3+}}\]

  • \[\ce{Fe^{3+}, Mn^{2+}}\]

  • \[\ce{Fe^{3+}, Co^{3+}}\]

  • \[\ce{Sc^{3+}, Cr^{3+}}\]

MCQ
रिकाम्या जागा भरा
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उत्तर

The pair of ions having same electronic configuration is \[\ce{Fe^{3+}, Mn^{2+}}\].

Explanation:

\[\ce{Fe^{3+}}\] electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d5 4s2

\[\ce{Mn^{2+}}\] electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d5 4s2

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पाठ 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ १६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
पाठ 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 14 | पृष्ठ १६

संबंधित प्रश्‍न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.


Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


Explain the anomalous behaviour of copper.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 4, l = 2


Write condensed orbital notation of electronic configuration of the following element:

Lithium (Z = 3)


Write condensed orbital notation of electronic configuration of the following element:

Oxygen (Z = 8)


Explain in brief, the significance of the azimuthal quantum number.


If n = 3, what are the quantum number l and m?


Write a note on ‘Principal Quantum number.


Indicate the number of unpaired electron in:

Cr (Z = 24)


The principal quantum number (n) and magnetic quantum number (ml) for the valence electrons of rubidium atom (Z = 37) are ____________ respectively.


Which one of the following orders is CORRECT in case of energy of the given subshells?

P: n = 4; l = 3

Q: n = 5; I = 1

R: n = 5; l = 0

S: n = 4; l = 2


Number of angular nodes for 4d orbital is ______.


Calculate the total number of angular nodes and radial nodes present in 3p orbital.


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5p, 4d, 5d, 4f, 6s


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5f, 6d, 7s, 7p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2

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