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State Heisenberg uncertainty principle. - Chemistry

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प्रश्न

State Heisenberg uncertainty principle.

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उत्तर

Heisenberg's uncertainty principle states that “It is impossible to determine simultaneously, the exact position and exact momentum (or velocity) of an electron”.

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पाठ 4: Structure of Atom - Exercises [पृष्ठ ५४]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 4 Structure of Atom
Exercises | Q 5. (C) | पृष्ठ ५४

संबंधित प्रश्‍न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.


Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


Choose the correct option.

“No two electrons in the same atoms can have identical set of four quantum numbers”. This statement is known as -


Choose the correct option.

Principal Quantum number describes -


Give the names of quantum numbers.


Explain the anomalous behaviour of chromium.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 3, l = 2


Write electronic configurations of \[\ce{Fe, Fe2+, Fe3+}\].


Write condensed orbital notation of electronic configuration of the following element:

Carbon (Z = 6)


Write condensed orbital notation of electronic configuration of the following element:

Chlorine (Z = 17)


If n = 3, what are the quantum number l and m?


The electronic configuration of oxygen is written as 1s2 2s2 \[\ce{2p^2_{{x}}}\] \[\ce{2p^1_{{y}}}\] \[\ce{2p^1_{{z}}}\] and not as 1s2 2s2 \[\ce{2p^2_{{x}}}\], \[\ce{2p^2_{{y}}}\] \[\ce{2p^0_{{z}}}\], Explain.


Write a note on ‘Principal Quantum number.


Indicate the number of unpaired electron in:

Cr (Z = 24)


The principal quantum number (n) and magnetic quantum number (ml) for the valence electrons of rubidium atom (Z = 37) are ____________ respectively.


Which mineral among the following contains vanadium in it?


The number of radial nodes for 3p orbital is ______.


Total number of orbitals associated with third shell will be ______.


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.


Calculate the total number of angular nodes and radial nodes present in 3p orbital.


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

4s, 3s, 3p, 4d


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5f, 6d, 7s, 7p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?


Match the following species with their corresponding ground state electronic configuration.

Atom / Ion Electronic configuration
(i) \[\ce{Cu}\] (a) 1s2 2s2 2p6 3s2 3p6 3d10
(ii) \[\ce{Cu^{2+}}\] (b) 1s2 2s2 2p6 3s2 3p6 3d10 4s2
(iii) \[\ce{Zn^{2+}}\] (c) 1s2 2s2 2p6 3s2 3p6 3d10 4s1
(iv) \[\ce{Cr^{3+}}\] (d) 1s2 2s2 2p6 3s2 3p6 3d9
  (e) 1s2 2s2 2p6 3s2 3p6 3d3

Match the following

(i) Photon (a) Value is 4 for N shell
(ii) Electron (b) Probability density
(iii) ψ2 (c) Always positive value
(iv) Principal quantum number n (d) Exhibits both momentum and wavelength

Choose the INCORRECT statement


In the case of R, S configuration the group having the highest priority is ______.


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