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प्रश्न
Answer in one sentence:
Name the element that shows the simplest emission spectrum.
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उत्तर
The element that shows the simplest emission spectrum is hydrogen.
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संबंधित प्रश्न
The radii of Bohr orbit are directly proportional to ______
According to Bohr's second postulate, the angular momentum of the electron is the integral multiple of `h/(2pi)`. The S.I unit of Plank constant h is the same as ______
For the hydrogen atom, the minimum excitation energy ( of n =2) is ______
The speed of electron having de Broglie wavelength of 10 -10 m is ______
(me = 9.1 × 10-31 kg, h = 6.63 × 10-34 J-s)
If aO is the Bohr radius and n is the principal quantum number then, state the relation for the radius of nth orbit of the electron in terms of Bohr radius and principal quantum number.
The angular momentum of an electron in the 3rd Bohr orbit of a Hydrogen atom is 3.165 × 10-34 kg m2/s. Calculate Plank’s constant h.
Calculate the shortest wavelength in the Paschen series if the longest wavelength in the Balmar series is 6563 Ao.
Using the expression for the radius of orbit for the Hydrogen atom, show that the linear speed varies inversely to the principal quantum number n the angular speed varies inversely to the cube of principal quantum number n.
Which of the following series of transitions in the spectrum of hydrogen atom falls in ultraviolet region?
Bohr model is applied to a particle of mass 'm' and charge 'q' is moving in a plane under the influence of a transverse magnetic field 'B. The energy of the charged particle in the nth level will be (h = Planck's constant).
With the increase in principal quantum number, the energy difference between the two successive energy levels ____________.
When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the ______.
In Bohr's model of hydrogen atom, the period of revolution of the electron in any orbit is proportional to ______.
For an electron, discrete energy levels are characterised by ____________.
If the speed of an electron of hydrogen atom in the ground state is 2.2 x 106 m/s, then its speed in the third excited state will be ______.
Angular speed of an electron in the ground state of hydrogen atom is 4 × 1016 rad/s. What is its angular speed in 4th orbit?
In Bohr model, speed of electron in nth orbit of hydrogen atom is ______. (b = Planck's constant, n = principal quantum number, ∈0 is the permittivity of free space, e = electronic charge)
In Bohr's model of hydrogen atom, which of the following pairs of quantities are quantized?
If n is principal quantum number and r is the radius of the orbit in which electron revolves around nucleus, then its kinetic energy is ____________.
When an electron in hydrogen atom jumps from third excited state to the ground state, the de-Broglie wavelength associated with the electron becomes ____________.
In any Bohr orbit of hydrogen atom, the ratio of K.E to P.E of revolving electron at a distance 'r' from the nucleus is ______.
The radius of orbit of an electron in hydrogen atom in its ground state is 5.3 x 10-11 m After collision with an electron, it is found to have a radius of 13.25 x 10-10 m. The principal quantum number n of the final state of the atom is ______.
The relation between magnetic moment of revolving electron 'M' and principle quantum number 'n' is ______.
An electron of mass m and charge e initially at rest gets accelerated by a constant electric field E. The rate of change of de-Broglie wavelength of this electron at time t ignoring relativistic effects is ______.
The speed of an electron in ground state energy level is 2.6 × 106 ms-1, then its speed in third excited state will be ______.
In Bohr’s atomic model, speed and time period of revolution of an electron in n = 3 level are respectively.
Calculate the radius of the first Bohr orbit in the hydrogen atom.
Show that the angular speed of an electron in the nth Bohr orbit is w = `(πme^4)/(2ε_0^2h^3n^3)` and the corresponding frequency of the revolution of the electron is f = `(me^4)/(4ε_0^2h^3n^3)`.
