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Match species given in Column I with the electronic configuration given in Column II. Column I Column II (i) Cr (a) [Ar]3d84s0 (ii) FeX2+ (b) [Ar]3d104s1 (iii) NiX2+ (c) [Ar]3d64s0 (iv) Cu (d)

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प्रश्न

Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2
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उत्तर

Column I Column II
(i) \[\ce{Cr}\] (d) [Ar] 3d54s1
(ii) \[\ce{Fe^{2+}}\] (c) [Ar]3d64s0
(iii) \[\ce{Ni^{2+}}\] (a) [Ar]3d84s0
(iv) \[\ce{Cu}\] (b) [Ar]3d104s1
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पाठ 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ २२]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 47 | पृष्ठ २२

संबंधित प्रश्‍न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


Choose the correct option.

p-orbitals are _________ in shape.


Choose the correct option.

Principal Quantum number describes -


Define the term Electronic configuration.


State Hund’s rule of maximum multiplicity with a suitable example.


Write condensed orbital notation of electronic configuration of the following element:

Lithium (Z = 3)


Write condensed orbital notation of electronic configuration of the following element:

Oxygen (Z = 8)


Write condensed orbital notation of electronic configuration of the following element:

Calcium (Z = 20)


If n = 3, what are the quantum number l and m?


The three electrons have the following set of quantum numbers:

X = 6, 1, −1, `+1/2`

Y = 6, 0, 0, `+1/2`

Z = 5, 1, 0, `+1/2`

Identify the CORRECT statement.


Which of the following has a greater number of electrons than neutrons?

(Mass number of Mg, C, O and Na is 24, 12, 16 and 23 respectively).


Which one of the following is NOT possible?


Which of the following sets of quantum numbers are correct?

  `n` `l` `m_l`
(i) 1 1 +2
(ii) 2 1 +1
(iii) 3 2 –2
(iv) 3 4 –2

The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

1s, 2s, 3s, 2p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5f, 6d, 7s, 7p


Choose the INCORRECT statement


Which of the following is the correct plot for the probability density ψ2 (r) as a function of distance 'r' of the electron from the nucleus for 2s orbitals?


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