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प्रश्न
Match the following
| (i) Photon | (a) Value is 4 for N shell |
| (ii) Electron | (b) Probability density |
| (iii) ψ2 | (c) Always positive value |
| (iv) Principal quantum number n | (d) Exhibits both momentum and wavelength |
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उत्तर
| (i) Photon | (d) Exhibits both momentum and wavelength |
| (ii) Electron | (d) Exhibits both momentum and wavelength |
| (iii) ψ2 | (b) Probability density (c) Always positive value |
| (iv) Principal quantum number n |
(a) Value is 4 for N shell |
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संबंधित प्रश्न
Using s, p, d notations, describe the orbital with the following quantum numbers n = 3; l =1.
Define the term Electronic configuration.
State and explain Pauli’s exclusion principle.
State Hund’s rule of maximum multiplicity with a suitable example.
Write orbital notations for the electron in orbitals with the following quantum numbers.
n = 4, l = 2
Write condensed orbital notation of electronic configuration of the following element:
Lithium (Z = 3)
Write condensed orbital notation of electronic configuration of the following element:
Calcium (Z = 20)
Using the concept of quantum numbers, calculate the maximum numbers of electrons present in the ‘M’ shell. Give their distribution in shells, subshells, and orbitals.
Indicate the number of unpaired electron in:
Cr (Z = 24)
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The designation of a subshell with n = 6 and l = 2 is ____________.
How many electrons in 19K have n = 3, l = 1?
Which one of the following is NOT possible?
Number of angular nodes for 4d orbital is ______.
Total number of orbitals associated with third shell will be ______.
Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.
Calculate the total number of angular nodes and radial nodes present in 3p orbital.
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, arrange the following orbitals in the increasing order of energy.
5p, 4d, 5d, 4f, 6s
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
5p, 5d, 5f, 6s, 6p
In the case of R, S configuration the group having the highest priority is ______.
