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Match species given in Column I with the electronic configuration given in Column II. Column I Column II (i) Cr (a) [Ar]3d84s0 (ii) FeX2+ (b) [Ar]3d104s1 (iii) NiX2+ (c) [Ar]3d64s0 (iv) Cu (d)

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प्रश्न

Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2
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उत्तर

Column I Column II
(i) \[\ce{Cr}\] (d) [Ar] 3d54s1
(ii) \[\ce{Fe^{2+}}\] (c) [Ar]3d64s0
(iii) \[\ce{Ni^{2+}}\] (a) [Ar]3d84s0
(iv) \[\ce{Cu}\] (b) [Ar]3d104s1
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अध्याय 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ २२]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 47 | पृष्ठ २२

संबंधित प्रश्न

Choose the correct option.

Principal Quantum number describes -


Give the names of quantum numbers.


State Hund’s rule of maximum multiplicity with a suitable example.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 3, l = 2


Write electronic configurations of \[\ce{Fe, Fe2+, Fe3+}\].


Write condensed orbital notation of electronic configuration of the following element:

Carbon (Z = 6)


Write condensed orbital notation of electronic configuration of the following element:

Calcium (Z = 20)


Using the concept of quantum numbers, calculate the maximum numbers of electrons present in the ‘M’ shell. Give their distribution in shells, subshells, and orbitals.


Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).


The designation of a subshell with n = 6 and l = 2 is ____________.


How many electrons in 19K have n = 3, l = 1?


Which one of the following is NOT possible?


Which of the following options does not represent ground state electronic configuration of an atom?


The number of radial nodes for 3p orbital is ______.


Total number of orbitals associated with third shell will be ______.


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5p, 4d, 5d, 4f, 6s


The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?


What is the difference between the terms orbit and orbital?


Match the following

(i) Photon (a) Value is 4 for N shell
(ii) Electron (b) Probability density
(iii) ψ2 (c) Always positive value
(iv) Principal quantum number n (d) Exhibits both momentum and wavelength

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