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Match species given in Column I with the electronic configuration given in Column II. Column I Column II (i) Cr (a) [Ar]3d84s0 (ii) FeX2+ (b) [Ar]3d104s1 (iii) NiX2+ (c) [Ar]3d64s0 (iv) Cu (d) - Chemistry

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प्रश्न

Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2
जोड़ियाँ मिलाइएँ
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उत्तर

Column I Column II
(i) \[\ce{Cr}\] (d) [Ar] 3d54s1
(ii) \[\ce{Fe^{2+}}\] (c) [Ar]3d64s0
(iii) \[\ce{Ni^{2+}}\] (a) [Ar]3d84s0
(iv) \[\ce{Cu}\] (b) [Ar]3d104s1
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अध्याय 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ २२]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 47 | पृष्ठ २२

संबंधित प्रश्न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.


Explain the anomalous behaviour of chromium.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 2, l = 1


Draw shapes of 2s orbitals.


Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).


The principal quantum number (n) and magnetic quantum number (ml) for the valence electrons of rubidium atom (Z = 37) are ____________ respectively.


How many electrons in 19K have n = 3, l = 1?


Which of the following has a greater number of electrons than neutrons?

(Mass number of Mg, C, O and Na is 24, 12, 16 and 23 respectively).


The probability density plots of 1s and 2s orbitals are given in Figure:


The density of dots in a region represents the probability density of finding electrons in the region.

On the basis of above diagram which of the following statements is incorrect?


Which of the following properties of atom could be explained correctly by Thomson Model of atom?


Number of angular nodes for 4d orbital is ______.


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

In which of the following pairs, the ions are iso-electronic?

(i) \[\ce{Na^{+}, Mg^{2+}}\]

(ii) \[\ce{Al3^{+}, O-}\]

(iii) \[\ce{Na+ , O2-}\]

(iv) \[\ce{N3-, Cl-}\]


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

1s, 2s, 3s, 2p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

4s, 3s, 3p, 4d


The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?


Match the quantum numbers with the information provided by these.

Quantum number Information provided
(i) Principal quantum number (a) orientation of the orbital
(ii) Azimuthal quantum number (b) energy and size of orbital
(iii) Magnetic quantum number (c) spin of electron
(iv) Spin quantum number (d) shape of the orbital

Choose the INCORRECT statement


Which of the following is not the permissible arrangement of electrons in an atom?


Which one of the following laws will represent the pairing of electrons in a subshell after each orbital is filled with one electron?


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