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Explain the anomalous behaviour of chromium.

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प्रश्न

Explain the anomalous behaviour of chromium.

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उत्तर

  1. Chromium (Cr) has atomic number 24.
  2. Its expected electronic configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d4.
  3. The 3d orbital is less stable, as it is not half-filled.
  4. Due to inter-electronic repulsion forces, one 4s electron enters into the 3d orbital. This makes the 4s and 3d orbitals half-filled, which gives extra stability, and the electronic configuration of Cr becomes 1s2 2s2 2p6 3s2 3p6 4s1 3d5.
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अध्याय 4: Structure of Atom - Exercises [पृष्ठ ५४]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
अध्याय 4 Structure of Atom
Exercises | Q 6. (I) | पृष्ठ ५४

संबंधित प्रश्न

Choose the correct option.

p-orbitals are _________ in shape.


Choose the correct option.

“No two electrons in the same atoms can have identical set of four quantum numbers”. This statement is known as -


Define the term Electronic configuration.


State and explain Pauli’s exclusion principle.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 2, l = 1


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 4, l = 2


Write condensed orbital notation of electronic configuration of the following element:

Lithium (Z = 3)


Write condensed orbital notation of electronic configuration of the following element:

Oxygen (Z = 8)


Write condensed orbital notation of electronic configuration of the following element:

Chlorine (Z = 17)


Write a note on ‘Principal Quantum number.


Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).


The principal quantum number (n) and magnetic quantum number (ml) for the valence electrons of rubidium atom (Z = 37) are ____________ respectively.


How many electrons in 19K have n = 3, l = 1?


The three electrons have the following set of quantum numbers:

X = 6, 1, −1, `+1/2`

Y = 6, 0, 0, `+1/2`

Z = 5, 1, 0, `+1/2`

Identify the CORRECT statement.


How many electrons can fit in the orbital for which n = 4 and l = 2?


Which of the following has a greater number of electrons than neutrons?

(Mass number of Mg, C, O and Na is 24, 12, 16 and 23 respectively).


Which one of the following is NOT possible?


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

Which of the following statements concerning the quantum numbers are correct?

(i) Angular quantum number determines the three dimensional shape of the orbital.

(ii) The principal quantum number determines the orientation and energy of the orbital.

(iii) Magnetic quantum number determines the size of the orbital.

(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.


Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5f, 6d, 7s, 7p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?


Match the following

(i) Photon (a) Value is 4 for N shell
(ii) Electron (b) Probability density
(iii) ψ2 (c) Always positive value
(iv) Principal quantum number n (d) Exhibits both momentum and wavelength

Choose the INCORRECT statement


In the case of R, S configuration the group having the highest priority is ______.


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