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Solve the following differential equation: ydydxxdydxy3-dydx=x2dydx - Mathematics and Statistics

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प्रश्न

Solve the following differential equation:

`"y"^3 - "dy"/"dx" = "x"^2 "dy"/"dx"`

बेरीज
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उत्तर

`"y"^3 - "dy"/"dx" = "x"^2 "dy"/"dx"`

∴ `"y"^3 = "dy"/"dx" + "x"^2 "dy"/"dx"`

∴ `"y"^3 = (1 + "x"^2)"dy"/"dx"`

∴ `1/(1 + "x"^2) "dx" = 1/"y"^3`dy

Integrating both sides, we get

`int 1/(1 + "x"^2) "dx" = int "y"^-3`dy

∴ `tan^-1 "x" = "y"^(-2)/-2 + "c"_1`

∴ `tan^-1 "x" = - 1/"2y"^2 + "c"_1`

∴ 2y2 tan-1 x = - 1 + 2c1y2

∴ 2y2 tan-1 x + 1 = cy2, where c = 2c1

This is the general solution.

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Formation of Differential Equations
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पाठ 6: Differential Equations - Exercise 6.3 [पृष्ठ २०१]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Exercise 6.3 | Q 2.08 | पृष्ठ २०१

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