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Find the differential equation of the family of parabolas with vertex at (0, –1) and having axis along the y-axis

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प्रश्न

Find the differential equation of the family of parabolas with vertex at (0, –1) and having axis along the y-axis

बेरीज
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उत्तर

Equation of the family of parabolas with vertex at (0, –1) and having axis along the y-axis is

(x – 0)2 = 4a(y + 1)

x2 = 4a(y + 1)  .......(1)

x2 = 4 ay + 4a

Differentiating equation (1) with respect to ‘x’, we get
2x = 4a y’

`(2x)/(y"'")` = 4a

Substituting 4a value in equation (1), we get

x² = `(2x)/(y"'") (y + 1)`

`x^2/x = 2/(y"'") (y + 1)`

x = `2/(y"'") (y + 1)`

xy’ = 2(y + 1)

xy’ = 2y + 2

xy’ – 2y – 2 = 0 is a required differential equation.

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पाठ 10: Ordinary Differential Equations - Exercise 10.3 [पृष्ठ १५४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 10 Ordinary Differential Equations
Exercise 10.3 | Q 5 | पृष्ठ १५४

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