Advertisements
Advertisements
प्रश्न
In the following pair of halogen compounds, which compound undergoes a faster SN1 reaction?
Advertisements
उत्तर
The activity of halogen compounds in SN1 reaction depends on the stability of the carbocation formed due to ionization. The order of stability is tertiary > secondary > primary. Hence, 2° alkyl chloride is more active than 1° alkyl chloride. Hence, 2° alkyl chloride is more active in SN1 reaction.
The halogen which reacts faster due to the greater stability of the 2° carbocation than the 1° carbocation is:
APPEARS IN
संबंधित प्रश्न
Write the structures of A, B and C in the following:
Write the isomers of the compound having the formula C4H9Br.
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH2Br + KCN ->[aq{.} ethanol]}\]
Write the mechanism of the following reaction:
\[\ce{{n}BuBr + KCN ->[EtOH-H2O] {n}BuCN}\]
The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.
What happens when ethyl chloride is treated with aqueous KOH?
The stability order for carbocation is _______.
(A) 2° > 3° > 1°
(B) 3° > 2° > 1°
(C) 3° > 1° > 2°
(D) 1° > 3° > 2°
Given reasons: SN1 reactions are accompanied by racemization in optically active alkyl halides.
What is the action of the following on ethyl bromide
alcoholic solution of potassium hydroxide.
The reaction of C6H5–CH=CH–CH3 with HBr produces:
Which of the following alkyl halides will undergo SN1 reaction most readily?
Complete the following analogy:
Same molecular formula but different structures: A : : Non superimposable mirror images: B
Among the following compounds I - IV, which one forms a yellow precipitate on reacting sequentially with (i) NaOH (ii) dil. HNO3 (iii) AgNO3?
 |
 |
 |
 |
| I | II | III | IV |
The number of chiral carbons present in the molecule given below is ______.
Identify the product in the following reaction: 
Discuss SN2 mechanism of methyl bromide using aqueous KOH.
Which one of the following chlorohydrocarbons readily undergoes solvolysis?
Consider the reactions,
(i) \[\begin{array}{cc}
\phantom{}\ce{\underset{}{(CH3)2CH - CH2Br} ->[C2H5OH] \underset{}{(CH3)2CH - CH2OC2H5 + HBr}}\\
\end{array}\]
(ii) \[\begin{array}{cc}
\phantom{}\ce{\underset{}{(CH3)2CH - CH2Br} ->[C2H5O-] \underset{}{(CH3)2CH - CH2OC2H5 + Br-}}\\
\end{array}\]
The mechanisms of reactions (i) and (ii) are respectively:
