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प्रश्न
In the following pair of halogen compounds, which compound undergoes a faster SN1 reaction?
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उत्तर
The activity of halogen compounds in SN1 reaction depends on the stability of the carbocation formed due to ionization. The order of stability is tertiary > secondary > primary. Hence, 2° alkyl chloride is more active than 1° alkyl chloride. Hence, 2° alkyl chloride is more active in SN1 reaction.
The halogen which reacts faster due to the greater stability of the 2° carbocation than the 1° carbocation is:
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संबंधित प्रश्न
Discuss the mechanism of alkaline hydrolysis of bromomethane.
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\[\ce{C2H5OH ->[SOCl2][Pyridine] A ->[KCN {(alc.)}] B ->[2H2O/H^+] C}\]
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1-Bromoethane, 1-Bromopropane, 1-Bromobutane, Bromobenzene
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(i) Both the compounds form same product on treatment with alcoholic KOH.
(ii) Both the compounds form same product on treatment with aq.NaOH.
(iii) Both the compounds form same product on reduction.
(iv) Both the compounds are optically active.
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Complete the reaction with the main product formed:
Convert bromoethane to propanamine.
Which alkyl halide from the following pair would you expect to react more rapidly by an SN2 mechanism? Explain your answer.
\[\begin{array}{cc}
\ce{CH3CHCH2CH2Br}\\
|\phantom{.............}\\
\ce{CH3}\phantom{..........}\\
\end{array}\] or \[\begin{array}{cc}
\ce{CH3CH2CHCH2Br}\\
|\\
\phantom{...}\ce{CH3}\\
\end{array}\]
The compound that will undergo SN1 reaction with the fastest rate is:
