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प्रश्न
Consider the situation shown in figure. If the closed loop is completely enclosed in the circuit containing the switch, the closed loop will show _______________ .

पर्याय
an anticlockwise current-pulse
a clockwise current-pulse
an anticlockwise current-pulse and then a clockwise current-pulse
a clockwise current-pulse and then an anticlockwise current-pulse
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उत्तर
an anticlockwise current-pulse and then a clockwise current-pulse

According to Lenz's law, the induced current in the loop will be such that it opposes the increase in the magnetic field due to current flow in the circuit. Therefore, the direction of the induced current when the switch is closed is anti-clockwise.
Similarly, when the switch is open, there is a sudden fall in the current, leading to decrease in the magnetic field at the centre of the loop. According to Lenz's law, the induced current in the loop is such that it opposes the decrease in the magnetic field. Therefore, the direction of the induced current when the switch is open is clockwise.
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What happens as the rate of change of magnetic flux becomes greater?
Why must continuous mechanical work be supplied to an AC generator?
For a triangular loop leaving an out-of-page magnetic field, what is the induced current direction and path?
