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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is ______.

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प्रश्न

In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is ______.

विकल्प

  • 1.3 V

  • 2.3 V

  • 0

  • 0.5 V

MCQ
रिक्त स्थान भरें
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उत्तर

In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is 2.3 V.

Explanation:

Let us consider figure 2.3 V given above in the problem, suppose the potential difference between A and B is VAB.

Then, `V_(AB) - 0.3 = [(r_1 + r_2)10^3] xx (0.2 xx 10^-3)`  .....[∵ VAB = ir]

= `[(5 + 5)10^3] xx (0.2 xx 10^-3)]`

= `10 xx 10^3 xx 0.2 xx 10^-3`

= 2

⇒ VAB = 2 + 0.3 = 2.3 V

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अध्याय 14: Semiconductor Electronics - Exercises [पृष्ठ ८९]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
अध्याय 14 Semiconductor Electronics
Exercises | Q 14.07 | पृष्ठ ८९

वीडियो ट्यूटोरियलVIEW ALL [2]

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