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प्रश्न
Figure shows the velocity-time graph of a particle moving in a straight line.
(i) State the nature of motion of particle.
(ii) Find the displacement of particle at t = 6 s.
(iii) Does the particle change its direction of motion?
(iv) Compare the distance travelled by the particle from 0 to 4 s and from 4 s to 6 s.
(v) Find the acceleration from 0 to 4 s and retardation from 4 s to 6 s.
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उत्तर
(i) From 0 to 4 seconds, the motion is uniformly accelerated and from 4 to 6 seconds, the motion is uniformly retarded.
(ii) Displacement of the particle at 6 s = (1/2) (6) (2) = 6 m
(iii) The particle does not change its direction of motion.
(iv) Distance travelled by the particle from 0 to 4s (D1) = (1/2) (4) (2) = 4 m
Distance travelled by the particle from 4 to 6s (D2) = (1/2) (2) (2) = 2 m
D1:D2:: 4:2
D1:D2:: 2:1
(v) Acceleration from 0 to 4 s = (2/4) ms-2 or 0.5 ms-2
Retardation from 4 s to 6 s = (2/2) ms-2 or 1 ms-2.
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संबंधित प्रश्न
Which of the following is true for displacement?
- It cannot be zero.
- Its magnitude is greater than the distance travelled by the object.
Can displacement be zero even if the distance is not zero? Give one example to explain your answer.
What can you say about the nature of motion of a body if its displacement-time graph is A straight line inclined to the time axis with an acute angle?
Give an example of a body which covers a certain distance, but its displacement is zero.
From the displacement – time graph shown given below calculate :
- Velocity between 0 – 2 s.
- Velocity between 8 s – 12 s.
- Average velocity between 5 s – 12 s.
Calculate the distance and displacement in the following case:
Ashok starts from his house and travels 3 km to reach his school. On finding the school gates closed, he returns to his house. What is?
The displacement of Ashok
Displacement / Time : Velocity :: Speed / Time : ______.
Which of the following is correct?
Give some examples for vector quantity.
