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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 16 - Circle [Latest edition]

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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 16 - Circle - Shaalaa.com
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Solutions for Chapter 16: Circle

Below listed, you can find solutions for Chapter 16 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.


Exercise 16(A)Exercise 16(B)TEST YOURSELF
Exercise 16(A) [Pages 240 - 241]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 16 Circle Exercise 16(A) [Pages 240 - 241]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 240

A chord of length 6 cm is drawn in a circle of diameter 10 cm, its distance from the centre of the circle is ______.

  • 6 cm

  • 8 cm

  • 4 cm

  • 10 cm

1. (b)Page 240

The given figure shows two concentric circles and AD is a chord. The relation between AB and CD is:

  • AB = CD

  • AB > CD

  • AB < CD

  • AB ≠ CD

1. (c)Page 240

In the given figure, chord AB is larger than chord CD. The relation between OM and ON is:

  • OM = ON

  • OM < ON

  • OM > ON

  • OM + ON = AB

1. (d)Page 240

The line joining the mid-points of two chords of a circle passes through its centre, then the chords are ______.

  • not parallel to each other

  • equal to each other

  • parallel to each other

  • not equal to each other

1. (e)Page 240

In the given figure, O and O' are centres of two circles, AB//CD//OO′, then which of the following is not true:

  • AB = 2 × OO'

  • CD = 2 × OO'

  • AB = CD

  • AB ≠ CD

2.Page 240

A chord of length 8 cm is drawn at a distance of 3 cm from the center of the circle.
Calculate the radius of the circle.

3.Page 240

The radius of a circle is 17.0 cm and the length of the perpendicular drawn from its center to a chord is 8.0 cm.
Calculate the length of the chord.

4.Page 240

A chord of length 24 cm is at a distance of 5 cm from the center of the circle. Find the length of the chord of the same circle which is at a distance of 12 cm from the center.

5.Page 240

In the following figure, AD is a straight line, OP ⊥ AD and O is the centre of both circles. If OA = 34cm, OB = 20 cm and OP = 16 cm;
find the length of AB.

6.Page 240

In a circle of radius 17 cm, two parallel chords of lengths 30 cm and 16 cm are drawn. Find the distance between the chords, if both the chords are:

  1. on the opposite sides of the centre;
  2. on the same side of the centre.
7.Page 240

Two parallel chords are drawn in a circle of diameter 30.0 cm. The length of one chord is 24.0 cm and the distance between the two chords is 21.0 cm;

find the length of another chord.

8.Page 240

A chord CD of a circle whose center is O is bisected at P by a diameter AB. Given OA = OB = 15 cm and OP = 9 cm.
Calculate the lengths of: (i) CD ; (ii) AD ; (iii) CB.

9.Page 240

A straight line is drawn cutting two equal circles and passing through the mid-point M of the line joining their centers O and O'. Prove that the chords AB and CD, which are intercepted by the two circles, are equal.

10.Page 241

M and N are the mid-points of two equal chords AB and CD respectively of a circle with center O.
Prove that: (i) ∠BMN = ∠DNM
                  (ii) ∠AMN = ∠CNM

11.Page 241

Two equal chords AB and CD of a circle with center O, intersect each other at point P inside the circle.
Prove that: (i) AP = CP ; (ii) BP = DP

12.Page 241

In the following figure, OABC is a square. A circle is drawn with O as centre which meets OC at P and OA at Q.
Prove that:
( i ) ΔOPA ≅ ΔOQC 
( ii ) ΔBPC ≅ ΔBQA

13.Page 241

The length of the common chord of two intersecting circles is 30 cm. If the diameters of these two circles are 50 cm and 34 cm, calculate the distance between their centers.

14.Page 241

The line joining the midpoints of two chords of a circle passes through its center.

Prove that the chords are parallel.

15.Page 241

In the following figure, the line ABCD is perpendicular to PQ; where P and Q are the centers of the circles.
Show that:
(i) AB = CD ;
(ii) AC = BD.

Exercise 16(B) [Pages 244 - 245]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 16 Circle Exercise 16(B) [Pages 244 - 245]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 244

In the given figure, arc APB = arc CQD, then:

  • AB = CD

  • AB > CD

  • AB < CD

  • none of the above

1. (b)Page 244

In the given figure, O is centre of the circle and ∠COD is greater than ∠AOB, then:

  • AB > CD

  • AB < CD

  • AB = CD

  • AB + CD = AD

1. (c)Page 244

In a circle, O is its centre and AB, CD are B its two chords. If AB : CD = 3 : 2, then ratio between ∠AOB and ∠COD is ______.

  • 1 : 1

  • 3 : 2

  • 2 : 5

  • 3 : 5

1. (d)Page 244

In the given figure, O is centre of the circle and ABC is an equilateral triangle, then ∠AOB is equal to:

  • 105°

  • 90°

  • 60°

  • 120°

1. (e)Page 244

In the given figure, O is centre of the circle and chord AB : chord CD = 5 : 3. If angle DOC = 60°; then ∠AOB is:

  • 120°

  • 75°

  • 100°

  • 80°

2.Page 244

In the given figure, a square is inscribed in a circle with center O. Find:

  1. ∠BOC
  2. ∠OCB
  3. ∠COD
  4. ∠BOD

Is BD a diameter of the circle?

3.Page 244

In the given figure, AB is a side of regular pentagon and BC is a side of regular hexagon.
(i) ∠AOB
(ii) ∠BOC
(iii) ∠AOC
(iv) ∠OBA
(v) ∠OBC
(vi) ∠ABC

4.Page 244

In the given figure, arc AB and arc BC are equal in length. If ∠AOB = 48°, find:
(i) ∠BOC
(ii) ∠OBC
(iii) ∠AOC
(iv) ∠OAC

5.Page 244

In the given figure, the lengths of arcs AB and BC are in the ratio 3:2. If ∠AOB = 96°, find: 

  1. ∠BOC
  2. ∠ABC

6.Page 244

In the given figure, AB = BC = DC and ∠AOB = 50°.
(i) ∠AOC
(ii) ∠AOD
(iii) ∠BOD
(iv) ∠OAC
(v) ∠ODA

7.Page 244

In the given figure, AB is a side of a regular hexagon and AC is a side of a regular eight-sided polygon.
Find:
(i) ∠AOB
(ii) ∠AOC
(iii) ∠BOC 
(iv) ∠OBC

8.Page 245

In the given figure, O is the center of the circle and the length of arc AB is twice the length of arc BC. If ∠AOB = 100°,
find: (i) ∠BOC (ii) ∠OAC

TEST YOURSELF [Pages 245 - 246]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 16 Circle TEST YOURSELF [Pages 245 - 246]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 245

In a circle with centre at point O, chord AB is a side of a square and chord BC is a side of regular hexagon. Then angle AOC is equal to ______.

  • 120°

  • 150°

  • 90°

  • none of these

1. (b)Page 245

AB (= 20 cm) is diameter of the given circle and AP (= 16 cm). The distance of chord AP from centre O is ______.

  • 12 cm

  • 18 cm

  • 9 cm

  • 6 cm

1. (c)Page 245

Given O is centre of the circle with chord AB = 8 cm. OA = 5 cm and OD ⊥ AB. The length of CD is ______.

  • 3 cm

  • 5 cm

  • 2 cm

  • none of these

1. (d)Page 245

AB and CD are chords of a circle with centre O, ∠AOB = 60° and angle ∠COD = 45°: the ratio between the lengths of chords AB and CD is ______.

  • 3 : 4

  • 4 : 3

  • 7 : 4

  • 7 : 3

1. (e)Page 245

Statement (1): O and O' are centres of two equal circles and ABCD is a straight line.

Statement (2): If OР ⊥ АВ, O'Q ⊥ CD and O'Q is greater than OP, then CD > AB.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (f)Page 245

Statement (1): In a circle with centre O, chord AB: chord BC = 1 : 3. If angle AOC is 160° ⇒ angle BOC = 120°.

Statement (2): AB : BC = 1 : 3 ⇒ ∠AOC = 3 × ∠AOB

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (g)Page 245

Assertion (A): In the given figure, chord AB = 8 cm, diameter CD = 20 cm, then length of OP = 10 cm.

Reason (R): OP = `sqrt(OA^2 - AP^2)` and CP = OC + OP.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

2.Page 246

The figure given below, shows a circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED = 8 cm and EB = 4 cm, find the radius of the circle.

3.Page 246

In the given figure, O is the centre of the circle. AB and CD are two chords of the circle. OM is perpendicular to AB and ON is perpendicular to CD. AB = 24 cm, OM = 5 cm, ON = 12 cm. Find the:

  1. radius of the circle.
  2. length of chord CD.

4.Page 246

AB and CD are two equal chords of a circle with center O which intersect each other at a right angle at point P.
If OM ⊥ AB and ON ⊥ CD;
show that OMPN is a square.

5.Page 246

The radius of a circle is 13 cm and the length of one of its chords is 24 cm.
Find the distance of the chord from the center.

6.Page 246

Prove that equal chords of congruent circles subtend equal angles at their center.

7.Page 246

Draw two circles of different radii. How many points these circles can have in common? What is the maximum number of common points?

8.Page 246

Suppose you are given a circle. Describe a method by which you can find the center of this circle.

9.Page 246

Given two equal chords AB and CD of a circle with center O, intersecting each other at point P.
Prove that:
(i) AP = CP
(ii) BP = DP 

10.Page 246

In a circle of radius 10 cm, AB and CD are two parallel chords of lengths 16 cm and 12 cm respectively.
Calculate the distance between the chords, if they are on:
(i) the same side of the center.
(ii) the opposite sides of the center.

11.Page 246

In the given figure, O is the center of the circle with radius 20 cm and OD is perpendicular to AB. If AB = 32 cm,
find the length of CD.

12.Page 246

In the given figure, AB and CD are two equal chords of a circle, with centre O. If P is the mid-point of chord AB, Q is the mid-point of chord CD and ∠POQ = 150°, find ∠APQ.

13.Page 246

In the given figure, AOC is the diameter of the circle, with centre O. If arc AXB is half of arc BYC, find ∠BOC.

14.Page 246

The circumference of a circle, with center O, is divided into three arcs APB, BQC, and CRA such that:
`"arc APB"/2 = "arc BQC"/3 = "arc CRA"/4`

Find ∠BOC.

Solutions for 16: Circle

Exercise 16(A)Exercise 16(B)TEST YOURSELF
Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 16 - Circle - Shaalaa.com

Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 16 - Circle

Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE 16 (Circle) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 16 Circle are .

Using Selina Concise Mathematics [English] Class 9 ICSE solutions Circle exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 9 ICSE students prefer Selina Textbook Solutions to score more in exams.

Get the free view of Chapter 16, Circle Concise Mathematics [English] Class 9 ICSE additional questions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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