Question

The radius of a circle is 13 cm and the length of one of its chords is 24 cm.
Find the distance of the chord from the center.

Answer 1

To find: OM

Given that AB = 24 cm
Since OM ⊥ AB
⇒ OM bisects AB
So, AM = 12 cm
In right ⇒ OMA,
OA² = OM²  + AM²
OM² = OA² - AM²
OM² = 13² - 12²
OM² = 25
OM² = 5 cm
Hence, the distance of the chord from the centre is 5 cm.