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Chapters
1: Rational and Irrational Numbers
Unit 2: Commercial Mathematics
2: Compound Interest (Stage 1) [Basic Concepts]
3: Compound Interest (Stage 2) [Applications]
Unit 3: Algebra
4: Expansions
5: Factorisation
6: Simultaneous (Linear) Equations [Including Problems]
7: Indices [Exponents]
8: Logarithms
Unit 4: Geometry
9: Triangles [Congruency in Triangles]
10: Isosceles Triangles [Including Inequalities]
11: Mid-point Theorem and Its Converse [Including Intercept Theorem]
12: Pythagoras Theorem [Proof and Simple Applications with Converse]
13: Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
14: Construction of Polygons (Using ruler and compass only)
15: Area Theorems [Proof and Use]
16: Circle
Unit 5: Statistics and Graph Work
17: Statistics
18: Mean and Median [For Ungrouped Data Only]
Unit 6: Mensuration
19: Area and Perimeter of Plane Figures
20: Solids [Surface Area and Volume of 3-D Solids]
Unit 7: Trigonometry
21: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
22: Solution of Right Triangles [Simple 2-D Problems Involving One Right-angled Triangle]
Unit 8: Co-Ordinate
23: Co-ordinate Geometry
24: Graphical Solution [Solution of Simultaneous Linear Equations, Graphically]
▶ 25: Distance Formula
![Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 25 - Distance Formula Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 25 - Distance Formula - Shaalaa.com](/images/concise-mathematics-english-class-9-icse_6:e09935b48e334a1e8f06ebb2011509f8.jpg)
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Solutions for Chapter 25: Distance Formula
Below listed, you can find solutions for Chapter 25 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 25 Distance Formula Exercise 25 [Pages 372 - 373]
Multiple Choice Type: Choose the correct answer from the options given below.
The distance between the points (7, −5) and (3, −1) is:
4 units
3 units
\[4\sqrt{2}\] units
5 units
The distance of the point (−4, 3) from the origin is ______.
5 units
−5 units
4 units
3 units
The distance between the points (−3, 2) and (x, 10) is 10 units. The value of x is ______.
3
−9
3 or −9
3 and −9
The point (x, y) is equidistant from the points (3, 6) and (−3, 4). The relation between x and y is ______.
3x − y = 5
3x − y − 5 = 0
y − 3x = 0
3x + y = 5
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is ______.
5 units
12 units
10 units
11 units
`7 + sqrt(5)` units
6 units
Find the distance between the following pairs of points:
(–3, 6) and (2, –6)
Find the distance between the following pairs of points:
(a, b), (−a, −b)
Find the distance between the following pairs of points:
`(3/5,2) and (-(1)/(5),1(2)/(5))`
Find the distance between the following pair of points:
`(sqrt(3)+1,1)` and `(0, sqrt(3))`
Find the distance between the origin and the point:
(-8, 6)
Find the distance between the origin and the point:
(-5, -12)
Find the distance between the origin and the point:
(8, −15)
The distance between the points (3, 1) and (0, x) is 5. Find x.
Find the co-ordinates of points on the x-axis which are at a distance of 17 units from the point (11, -8).
Find the coordinates of the points on the y-axis, which are at a distance of 10 units from the point (-8, 4).
A point A is at a distance of `sqrt(10)` unit from the point (4, 3). Find the co-ordinates of point A, if its ordinate is twice its abscissa.
A point P (2, -1) is equidistant from the points (a, 7) and (-3, a). Find a.
What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)?
Find a point on the y-axis which is equidistant from the points (5, 2) and (-4, 3).
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the ordinate of point P.
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.
A point P lies on the x-axis and another point Q lies on the y-axis.
If the abscissa of point P is -12 and the ordinate of point Q is -16; calculate the length of line segment PQ.
Show that the points P (0, 5), Q (5, 10) and R (6, 3) are the vertices of an isosceles triangle.
Prove that the points P (0, -4), Q (6, 2), R (3, 5) and S (-3, -1) are the vertices of a rectangle PQRS.
Prove that the points A (1, -3), B (-3, 0) and C (4, 1) are the vertices of an isosceles right-angled triangle. Find the area of the triangle.
Show that the points A (5, 6), B (1, 5), C (2, 1) and D (6, 2) are the vertices of a square ABCD.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 25 Distance Formula TEST YOURSELF [Pages 373 - 375]
Multiple Choice Type: Choose the correct answer from the options given below.
The distance of the point (−8, 6) from the x-axis is ______.
8
6
10
None of these
The distance of the point (−4, −3) from the origin is:
−10 units
10 units
\(\sqrt{4^2-3^2}\)
None of these
The coordinates of point P are ______.

(0, 5)
(5, 0)
(4, 3)
(3, 4)
AB (= 10 unit) is diameter of a circle with centre at point P = (x, 0) and point B = (0, y). The relation between x and y is:

x + y = 10
x + y = 25
\(x^2+y^2=5\)
\(x^2+y^2=25\)
Statement (1): For the point P, 𝑥 = −4 and 𝑦 = 3, the distance of P from origin is 3 + 4 = 7.
Statement (2): P = (−4, 3) and its distance from origin \[= \sqrt{(-4)^2 + (3)^2}\].
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Statement (1): The point P(𝑥, 𝑦) is at a distance of 6 unit from origin, then P lies in the first quadrant.
Statement (2): Point P can lie in any quadrant.
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Assertion (A): If A = (2𝑥, 𝑦), B(𝑥, 2𝑦) and AB = 5 unit, then 𝑥 + 𝑦 = 5.
Reason (R): \[\sqrt{(x - 2x)^2 + (2y - y)^2} = 5\] \[\Rightarrow x^2 + y^2 = 25\]
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A.
Both A and R are true and R is the incorrect reason for A.
Assertion (A): The distance between the points A(𝑥, 2𝑥) and B(𝑥, 0) is 4 unit, the point B is (2, 0).
Reason (R): \[\sqrt{(x - x)^2 + (2x - 0)^2} = 4\] \[\Rightarrow x^2 = 4 \text{ and } x = \pm 2\]
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A.
Both A and R are true and R is the incorrect reason for A.
Find the points on the 𝑦-axis which are at a distance of \[2\sqrt{5}\] units from the point (−4, 7).
Find the value of k, if the point P (2, 4) is equidistant from the points A(5, k) and B (k, 7).
The centre of a circle is (2a, a – 7). Find the values of a if the circle passes through the point (11, –9) and has diameter `10sqrt(2)` units.
Show that (-3, 2), (-5, -5), (2, -3) and (4, 4) are the vertices of a rhombus.
Points A (-3, -2), B (-6, a), C (-3, -4) and D (0, -1) are the vertices of quadrilateral ABCD; find a if 'a' is negative and AB = CD.
The vertices of a triangle are (5, 1), (11, 1) and (11, 9). Find the co-ordinates of the circumcentre of the triangle.
Given A = (3, 1) and B = (0, y - 1). Find y if AB = 5.
Given A = (x + 2, -2) and B (11, 6). Find x if AB = 17.
The centre of a circle is (2x - 1, 3x + 1). Find x if the circle passes through (-3, -1) and the length of its diameter is 20 unit.
The length of line PQ is 10 units and the co-ordinates of P are (2, -3); calculate the co-ordinates of point Q, if its abscissa is 10.
Point P (2, -7) is the center of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2, -4); calculate the length of: AT

Point P (2, -7) is the centre of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2, -4); calculate the length of AB.

Calculate the distance between the points P (2, 2) and Q (5, 4) correct to three significant figures.
Calculate the distance between A (7, 3) and B on the x-axis, whose abscissa is 11.
Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.
Find the point on y-axis whose distances from the points A (6, 7) and B (4, -3) are in the ratio 1: 2.
The distances of point P (x, y) from the points A (1, - 3) and B (- 2, 2) are in the ratio 2: 3.
Show that: 5x2 + 5y2 - 34x + 70y + 58 = 0.
The points A (3, 0), B (a, -2) and C (4, -1) are the vertices of triangle ABC right angled at vertex A. Find the value of a.
If two vertices of an equilateral triangle be (0, 0), (3, `sqrt3`), find the third vertex using distance formula.
Case-Study Based Question
A group of class IX students goes to a picnic during winter holidays. The positions of three friends Nitin, Rajesh and Kareem are shown by the points P, Q and R respectively.
- Find the distance between:
- Nitin and Rajesh
- Rajesh and Kareem
- Nitin and Kareem
- Show that P, Q and R are collinear.
- Find the point on X-axis which is equidistant from points Q and R.
- If R is taken as origin; what will be the coordinates of P and Q?

Rohan and Sohan stay in a village which are 50 km apart and are situated on Delhi Agra Highway as shown in the figure. Another highway YY’ crosses Agra Delhi highway at O (0, 0). A small local road PQ crosses both the highways at points A and B such that OA = 10 km and OB = 12 km. Also the villages of Sita and Gita are on the smaller highway YY’. Sita’s village is 12 km from O and Gita’s village is 15 km from O.
Now answer the following questions:
- Find the Coordinates of A and B.
- Find the Length of local road AB.
- What is the shortest distance Sohan will cover to reach Sita’s village.
- How far is Rohan’s village from Gita’s village?

Solutions for 25: Distance Formula
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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 25 - Distance Formula
Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE 25 (Distance Formula) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 25 Distance Formula are .
Using Selina Concise Mathematics [English] Class 9 ICSE solutions Distance Formula exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 9 ICSE students prefer Selina Textbook Solutions to score more in exams.
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