Advertisements
Advertisements
Question
Given A = (3, 1) and B = (0, y - 1). Find y if AB = 5.
Advertisements
Solution
AB = 5
AB2 = 25
(0 - 3)2 + (y - 1 - 1)2 = 25
9 + y2 + 4 - 4y = 25
y2 - 4y - 12 = 0
y2 - 6y + 2y - 12 = 0
y(y - 6) + 2(y - 6) = 0
(y - 6) (y + 2) = 0
y = 6, -2
APPEARS IN
RELATED QUESTIONS
Prove that the points A(1, 7), B(4, 2), C(−1, −1), and D(−4, 4) are the vertices of a square.
Find the distance between the following pair of points.
R(0, -3), S(0, `5/2`)
Find the distance between the following pairs of point in the coordinate plane :
(7 , -7) and (2 , 5)
Find the distance between the following point :
(sec θ , tan θ) and (- tan θ , sec θ)
A(-2, -3), B(-1, 0) and C(7, -6) are the vertices of a triangle. Find the circumcentre and the circumradius of the triangle.
Find the distance between the following pairs of points:
`(3/5,2) and (-(1)/(5),1(2)/(5))`
Find the distance between the following pair of points:
`(sqrt(3)+1,1)` and `(0, sqrt(3))`
A point A is at a distance of `sqrt(10)` unit from the point (4, 3). Find the co-ordinates of point A, if its ordinate is twice its abscissa.
Show that the points A (5, 6), B (1, 5), C (2, 1) and D (6, 2) are the vertices of a square ABCD.
Find the value of a, if the distance between the points A(–3, –14) and B(a, –5) is 9 units.
