Advertisements
Advertisements
Question
Show that the points (2, 0), (–2, 0), and (0, 2) are the vertices of a triangle. Also, a state with the reason for the type of triangle.
Advertisements
Solution
A ≡ (2, 0) ≡ (x1, y1)
B ≡ (–2 , 0) ≡ (x2, y2)
C ≡ (0, 2) ≡ (x3, y3)

∴ ABC form a triangle.
AB = `sqrt ((x_2 - x_1)^2 + ("y"_2 - "y"_1)^2)`
= `sqrt ((-2-2)^2 + (0 - 0)^2)`
= `sqrt ((-4)^2 + 0)`
= `sqrt(16)`
= 4 units
AC = `sqrt ((x_3 - x_1)^2 + ("y"_3 - "y"_1)^2)`
= `sqrt ((0-2)^2 + (2 - 0)^2)`
= `sqrt ((-2)^2 + (2)^2)`
= `sqrt (4 + 4)`
= `sqrt(8)`
= `2sqrt(2)` units
BC = `sqrt ((x_3 - x_2)^2 + ("y"_3 - "y"_2)^2)`
= `sqrt ((0-(-2)^2) + (2 - 0)^2)`
= `sqrt ((0 + 2)^2 + (2 - 0)^2)`
= `sqrt ((2)^2 + (2)^2)`
= `sqrt(8)`
= `2sqrt(2)` units
So, if side AC and side BC are equal then the triangle is an isosceles triangle.
AB2 = BC2 + AC2
`(4)^2 = (2sqrt2)^2 + (2sqrt(2))^2`
16 = 8 + 8
16 = 16
So, it is a right-angle isosceles triangle.
APPEARS IN
RELATED QUESTIONS
Find the value of x, if the distance between the points (x, – 1) and (3, 2) is 5.
If the opposite vertices of a square are (1, – 1) and (3, 4), find the coordinates of the remaining angular points.
Find the values of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units.
Find the distance between the following pair of points:
(asinα, −bcosα) and (−acos α, bsin α)
Find the distance of the following points from the origin:
(iii) C (-4,-6)
AB and AC are the two chords of a circle whose radius is r. If p and q are
the distance of chord AB and CD, from the centre respectively and if
AB = 2AC then proove that 4q2 = p2 + 3r2.
Find the distance between the following pair of point in the coordinate plane :
(5 , -2) and (1 , 5)
Find the distance between the following pairs of point in the coordinate plane :
(4 , 1) and (-4 , 5)
Find the distance between the following point :
(Sin θ - cosec θ , cos θ - cot θ) and (cos θ - cosec θ , -sin θ - cot θ)
Find the coordinate of O , the centre of a circle passing through A (8 , 12) , B (11 , 3), and C (0 , 14). Also , find its radius.
Prove taht the points (-2 , 1) , (-1 , 4) and (0 , 3) are the vertices of a right - angled triangle.
Prove that the points (7 , 10) , (-2 , 5) and (3 , -4) are vertices of an isosceles right angled triangle.
Prove that the points (a, b), (a + 3, b + 4), (a − 1, b + 7) and (a − 4, b + 3) are the vertices of a parallelogram.
Prove that the points (0 , -4) , (6 , 2) , (3 , 5) and (-3 , -1) are the vertices of a rectangle.
Show that (-3, 2), (-5, -5), (2, -3) and (4, 4) are the vertices of a rhombus.
The length of line PQ is 10 units and the co-ordinates of P are (2, -3); calculate the co-ordinates of point Q, if its abscissa is 10.
The distances of point P (x, y) from the points A (1, - 3) and B (- 2, 2) are in the ratio 2: 3.
Show that: 5x2 + 5y2 - 34x + 70y + 58 = 0.
Find the distance of the following points from origin.
(a+b, a-b)
|
Tharunya was thrilled to know that the football tournament is fixed with a monthly timeframe from 20th July to 20th August 2023 and for the first time in the FIFA Women’s World Cup’s history, two nations host in 10 venues. Her father felt that the game can be better understood if the position of players is represented as points on a coordinate plane. |
- At an instance, the midfielders and forward formed a parallelogram. Find the position of the central midfielder (D) if the position of other players who formed the parallelogram are :- A(1, 2), B(4, 3) and C(6, 6)
- Check if the Goal keeper G(–3, 5), Sweeper H(3, 1) and Wing-back K(0, 3) fall on a same straight line.
[or]
Check if the Full-back J(5, –3) and centre-back I(–4, 6) are equidistant from forward C(0, 1) and if C is the mid-point of IJ. - If Defensive midfielder A(1, 4), Attacking midfielder B(2, –3) and Striker E(a, b) lie on the same straight line and B is equidistant from A and E, find the position of E.

