Advertisements
Advertisements
Question
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.
Advertisements
Solution
Since, the point Q lies on the y-axis, its abscissa is 0.
APPEARS IN
RELATED QUESTIONS
Find the point on the x-axis which is equidistant from (2, –5) and (–2, 9).
If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?
A(–8, 0), B(0, 16) and C(0, 0) are the vertices of a triangle ABC. Point P lies on AB and Q lies on AC such that AP : PB = 3 : 5 and AQ : QC = 3 : 5. Show that : PQ = `3/8` BC.
Find the distance between the points:
A(1, –3) and B(4, –6)
For what values of k are the points (8, 1), (3, –2k) and (k, –5) collinear ?
What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)?
Point P (2, -7) is the centre of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2, -4); calculate the length of AB.

Find the point on y-axis whose distances from the points A (6, 7) and B (4, -3) are in the ratio 1: 2.
The point which lies on the perpendicular bisector of the line segment joining the points A(–2, –5) and B(2, 5) is ______.
What is the distance of the point (– 5, 4) from the origin?
