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What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)? - Mathematics

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Question

What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)?

Sum
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Solution

Let the co-ordinates of the required point on x-axis be P (x, 0).

The given points are A (7, 6) and B (-3, 4).

Given, PA = PB

PA2 = PB2

(x - 7)2 + (0 - 6)2 = (x + 3)2 + (0 - 4)2

x2 + 49 - 14x + 36 = x2 + 9 + 6x + 16

60 = 20x

x = 3

Thus, the required point is (3, 0).

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Chapter 28: Distance Formula - Exercise 28 [Page 335]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 28 Distance Formula
Exercise 28 | Q 8 | Page 335

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