Question

What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)?

Answer 1

Let the co-ordinates of the required point on x-axis be P (x, 0).

The given points are A (7, 6) and B (-3, 4).

Given, PA = PB

PA² = PB²

(x - 7)² + (0 - 6)² = (x + 3)² + (0 - 4)²

x² + 49 - 14x + 36 = x² + 9 + 6x + 16

60 = 20x

x = 3

Thus, the required point is (3, 0).