Advertisements
Advertisements
प्रश्न
What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)?
Advertisements
उत्तर
Let the co-ordinates of the required point on x-axis be P (x, 0).
The given points are A (7, 6) and B (-3, 4).
Given, PA = PB
PA2 = PB2
(x - 7)2 + (0 - 6)2 = (x + 3)2 + (0 - 4)2
x2 + 49 - 14x + 36 = x2 + 9 + 6x + 16
60 = 20x
x = 3
Thus, the required point is (3, 0).
APPEARS IN
संबंधित प्रश्न
The x-coordinate of a point P is twice its y-coordinate. If P is equidistant from Q(2, –5) and R(–3, 6), find the coordinates of P.
Show that the points (a, a), (–a, –a) and (– √3 a, √3 a) are the vertices of an equilateral triangle. Also find its area.
Find the centre of the circle passing through (6, -6), (3, -7) and (3, 3)
If A and B are the points (−6, 7) and (−1, −5) respectively, then the distance
2AB is equal to
Find the distance between the following point :
(sin θ , cos θ) and (cos θ , - sin θ)
Find the coordinate of O , the centre of a circle passing through P (3 , 0), Q (2 , `sqrt 5`) and R (`-2 sqrt 2` , -1). Also find its radius.
Find the distance of the following points from origin.
(a cos θ, a sin θ).
The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = ______.
If the length of the segment joining point L(x, 7) and point M(1, 15) is 10 cm, then the value of x is ______.
What type of a quadrilateral do the points A(2, –2), B(7, 3), C(11, –1) and D(6, –6) taken in that order, form?
