Question

Find distance between point Q(3, –7) and point R(3, 3)

Solution: Suppose Q(x₁, y₁) and point R(x₂, y₂)

x₁ = 3, y₁ = –7 and x₂ = 3, y₂ = 3

Using distance formula,

d(Q, R) = `sqrt(square)`

∴ d(Q, R) = `sqrt(square - 100)`

∴ d(Q, R) =  `sqrt(square)`

∴ d(Q, R) = `square`

Answer 1

Suppose Q(x₁, y₁) and point R(x₂, y₂)

x₁ = 3, y₁ = –7 and x₂ = 3, y₂ = 3

Using distance formula,

d(Q, R) = \[\sqrt{\boxed{(x_2 - x_1)^2 + (y_2 - y_1)^2}}\]

= `sqrt((3 - 3)^2 - [3 - (- 7)]^2`

= `sqrt(0^2 + (10)^2)`

∴ d(Q, R) = \[\sqrt{\boxed{0} - 100}\]

∴ d(Q, R) = \[\sqrt{\boxed{100}}\]

∴ d(Q, R) = \[\boxed{10}\]