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Question
Find distance between point Q(3, –7) and point R(3, 3)
Solution: Suppose Q(x1, y1) and point R(x2, y2)
x1 = 3, y1 = –7 and x2 = 3, y2 = 3
Using distance formula,
d(Q, R) = `sqrt(square)`
∴ d(Q, R) = `sqrt(square - 100)`
∴ d(Q, R) = `sqrt(square)`
∴ d(Q, R) = `square`
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Solution
Suppose Q(x1, y1) and point R(x2, y2)
x1 = 3, y1 = –7 and x2 = 3, y2 = 3
Using distance formula,
d(Q, R) = \[\sqrt{\boxed{(x_2 - x_1)^2 + (y_2 - y_1)^2}}\]
= `sqrt((3 - 3)^2 - [3 - (- 7)]^2`
= `sqrt(0^2 + (10)^2)`
∴ d(Q, R) = \[\sqrt{\boxed{0} - 100}\]
∴ d(Q, R) = \[\sqrt{\boxed{100}}\]
∴ d(Q, R) = \[\boxed{10}\]
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