Advertisements
Advertisements
Questions
Find the distance between the following pairs of points:
(−5, 7), (−1, 3)
Find the distance between the following pairs of points:
P(-5, 7), Q(-1, 3)
Advertisements
Solution 1
Distance between (−5, 7) and (−1, 3) is given by
l = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`
l = `sqrt((-5-(-1))^2 + (7 -3)^2)`
= `sqrt((-4)^2+(4)^2)`
= `sqrt(16+16) `
= `sqrt32`
= `4sqrt2` units
Solution 2
Let the co-ordinates of point P are (x1, y1) and of point Q are (x2, y2)
P(–5, 7) = (x1, y1)
Q(–1, 3) = (x2, y2)
PQ = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)` ...(By distance formula)
= `sqrt((-1-(-5))^2+(3-7)^2)`
= `sqrt((-1+5)^2+(-4)^2)`
= `sqrt(4^2+16)`
= `sqrt(16 + 16)`
= `sqrt32`
= `sqrt(16xx2)`
= `sqrt16xxsqrt2`
= 4`sqrt2` units
RELATED QUESTIONS
Find the distance between the following pair of points:
(-6, 7) and (-1, -5)
Find the distance between the following pair of points:
(a+b, b+c) and (a-b, c-b)
If the point P(x, y ) is equidistant from the points A(5, 1) and B (1, 5), prove that x = y.
Find the distance between the points:
A(7, –4) and B(–5, 1)
Find the distance of the following points from the origin:
C(–4, –6)
Find the values of x for which the distance between the points P(x, 4) and Q(9, 10) is 10 units.
The centre of a circle passing through P(8, 5) is (x+l , x-4). Find the coordinates of the centre if the diameter of the circle is 20 units.
From the given number line, find d(A, B):

Find the distance between the following pair of points:
`(sqrt(3)+1,1)` and `(0, sqrt(3))`
Find the co-ordinates of points on the x-axis which are at a distance of 17 units from the point (11, -8).
A point P (2, -1) is equidistant from the points (a, 7) and (-3, a). Find a.
A point P lies on the x-axis and another point Q lies on the y-axis.
If the abscissa of point P is -12 and the ordinate of point Q is -16; calculate the length of line segment PQ.
Given A = (x + 2, -2) and B (11, 6). Find x if AB = 17.
Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.
The points A (3, 0), B (a, -2) and C (4, -1) are the vertices of triangle ABC right angled at vertex A. Find the value of a.
Find distance between points O(0, 0) and B(–5, 12).
Find distance between point A(–1, 1) and point B(5, –7):
Solution: Suppose A(x1, y1) and B(x2, y2)
x1 = –1, y1 = 1 and x2 = 5, y2 = –7
Using distance formula,
d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
∴ d(A, B) = `sqrt(square +[(-7) + square]^2`
∴ d(A, B) = `sqrt(square)`
∴ d(A, B) = `square`
Show that the points (0, –1), (8, 3), (6, 7) and (–2, 3) are vertices of a rectangle.
The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure is ______.

The points A(–1, –2), B(4, 3), C(2, 5) and D(–3, 0) in that order form a rectangle.
