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Find the distance between the following pairs of points: (−5, 7), (−1, 3)

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Questions

Find the distance between the following pairs of points:

(−5, 7), (−1, 3)

Find the distance between the following pairs of points:

P(-5, 7), Q(-1, 3)

Sum
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Solution 1

Distance between (−5, 7) and (−1, 3) is given by

l = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)` 

l = `sqrt((-5-(-1))^2 + (7 -3)^2)`

= `sqrt((-4)^2+(4)^2)`

= `sqrt(16+16) `

= `sqrt32`

= `4sqrt2` units

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Solution 2

Let the co-ordinates of point P are (x1, y1) and of point Q are (x2, y2)

P(–5, 7) = (x1, y1)

Q(–1, 3) = (x2, y2)

PQ = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`     ...(By distance formula)

= `sqrt((-1-(-5))^2+(3-7)^2)`

= `sqrt((-1+5)^2+(-4)^2)`

= `sqrt(4^2+16)`

= `sqrt(16 + 16)`

= `sqrt32`

= `sqrt(16xx2)`

= `sqrt16xxsqrt2`

= 4`sqrt2` units

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Chapter 7: Coordinate Geometry - EXERCISE 7.1 [Page 105]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 7 Coordinate Geometry
EXERCISE 7.1 | Q 1. (ii) | Page 105
Balbharati Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
Chapter 5 Co-ordinate Geometry
Practice Set 5.1 | Q 1. 2 | Page 107

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Case Study -2

A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.

It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.

Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -

  • Forward: As shown by players A, B, C and D.
  • Midfielders: As shown by players E, F and G.
  • Fullbacks: As shown by players H, I and J.
  • Goalie: As shown by player K.

Using the picture of a hockey field below, answer the questions that follow:

The point on x axis equidistant from I and E is ______.


The centre of a circle is (2a, a – 7). Find the values of a if the circle passes through the point (11, – 9) and has diameter `10sqrt(2)` units.


Find distance between points P(– 5, – 7) and Q(0, 3).

By distance formula,

PQ = `sqrt(square + (y_2 - y_1)^2`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(125)`

= `5sqrt(5)`


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