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Find the distance between the following pairs of points: (−5, 7), (−1, 3)

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Questions

Find the distance between the following pairs of points:

(−5, 7), (−1, 3)

Find the distance between the following pairs of points:

P(-5, 7), Q(-1, 3)

Sum
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Solution 1

Distance between (−5, 7) and (−1, 3) is given by

l = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)` 

l = `sqrt((-5-(-1))^2 + (7 -3)^2)`

= `sqrt((-4)^2+(4)^2)`

= `sqrt(16+16) `

= `sqrt32`

= `4sqrt2` units

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Solution 2

Let the co-ordinates of point P are (x1, y1) and of point Q are (x2, y2)

P(–5, 7) = (x1, y1)

Q(–1, 3) = (x2, y2)

PQ = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`     ...(By distance formula)

= `sqrt((-1-(-5))^2+(3-7)^2)`

= `sqrt((-1+5)^2+(-4)^2)`

= `sqrt(4^2+16)`

= `sqrt(16 + 16)`

= `sqrt32`

= `sqrt(16xx2)`

= `sqrt16xxsqrt2`

= 4`sqrt2` units

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Chapter 7: Coordinate Geometry - EXERCISE 7.1 [Page 105]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 7 Coordinate Geometry
EXERCISE 7.1 | Q 1. (ii) | Page 105
Balbharati Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
Chapter 5 Co-ordinate Geometry
Practice Set 5.1 | Q 1. 2 | Page 107

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