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Maharashtra State BoardSSC (English Medium) 10th Standard

Find distance between points P(– 5, – 7) and Q(0, 3). By distance formula, PQ = □+(y2-y1)2 = □+□ = □+□ = □+□ = 125 = 55

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Question

Find distance between points P(– 5, – 7) and Q(0, 3).

By distance formula,

PQ = `sqrt(square + (y_2 - y_1)^2`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(125)`

= `5sqrt(5)`

Sum
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Solution

By distance formula,

PQ = `sqrt(bb((x^2 - x_1)^2) + (y_2 - y_1)^2`

= `sqrt(bb(0 - (-5)^2) + bb(3 - (-7)^2))`

= `sqrt(bb((5)^2) + bb((10)^2))`

= `sqrt(bb25 + bb100)`

= `sqrt(125)`

= `5sqrt(5)`

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