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Question
Find the distance of a point (7 , 5) from another point on the x - axis whose abscissa is -5.
Sum
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Solution
Let the point on x - axis be (x , 0) given abscissa is -5.
∴ point is P (-5 , 0)
Let (7 , 5) be point A
AP = `sqrt ((7+5)^2 + (5 - 0)^2)`
`= sqrt (144 + 25)`
`= sqrt 169`
= 13 units
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