Advertisements
Advertisements
Question
If the points (2, 1) and (1, -2) are equidistant from the point (x, y), show that x + 3y = 0.
Advertisements
Solution
Let p(x, y), Q(2, 1), R(1, -2) be the given points
Here `x_1 = x`, `y_1 = y`
`x_2 = 2, y_2 = 1`
The distance between two points
p(x,y) and Q(2, 1) is given by
`PQ = sqrt((2- x)^2 + (1 - y)^2)`
Similarly
Now both these distance are given to be the same
PQ = PR
`sqrt((2- x)^2 + (1 - y)^2) = sqrt((1 - x)^2 + (-2 - y)^2)`
Squaring both the sides
`=> sqrt((2- x)^2 + (1 - y)^2) = sqrt((1 - x)^2 + (-2 - y))`
Squaring both the sides
`=> (2 - x)^2 + (1 - y)^2 = (1 - x)^2 + (-2 - y)^2`
`=> 4 + x^2 - 4x + 1 + y^2 - 2y = 1 + x^2- 2x + 4 + y^2 + 4y`
`=> 4 + x^2 - 4x + 1 + y^2 - 2y -1 - x^2 + 2x - 4 - y^2 - 4y = 0`
`=>-2x - 6y = 0`
`=> -2(x + 3y) = 0`
=> x + 3y = 0
Hence prove
APPEARS IN
RELATED QUESTIONS
If P (2, – 1), Q(3, 4), R(–2, 3) and S(–3, –2) be four points in a plane, show that PQRS is a rhombus but not a square. Find the area of the rhombus
Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2.
Show that the points A (1, −2), B (3, 6), C (5, 10) and D (3, 2) are the vertices of a parallelogram.
Show that the quadrilateral whose vertices are (2, −1), (3, 4) (−2, 3) and (−3,−2) is a rhombus.
If P (x , y ) is equidistant from the points A (7,1) and B (3,5) find the relation between x and y
Show that the points A(1, 2), B(1, 6), C(1 + 2`sqrt3`, 4) are vertices of an equilateral triangle.
The centre of a circle passing through P(8, 5) is (x+l , x-4). Find the coordinates of the centre if the diameter of the circle is 20 units.
Prove that the points (a, b), (a + 3, b + 4), (a − 1, b + 7) and (a − 4, b + 3) are the vertices of a parallelogram.
PQR is an isosceles triangle . If two of its vertices are P (2 , 0) and Q (2 , 5) , find the coordinates of R if the length of each of the two equal sides is 3.
Show that the points P (0, 5), Q (5, 10) and R (6, 3) are the vertices of an isosceles triangle.
Calculate the distance between the points P (2, 2) and Q (5, 4) correct to three significant figures.
Show that the quadrilateral with vertices (3, 2), (0, 5), (- 3, 2) and (0, -1) is a square.
The distance between the points (0, 5) and (–5, 0) is ______.
If the distance between the points (4, P) and (1, 0) is 5, then the value of p is ______.
The distance between the point P(1, 4) and Q(4, 0) is ______.
Case Study -2
A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.
It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.
Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -
- Forward: As shown by players A, B, C and D.
- Midfielders: As shown by players E, F and G.
- Fullbacks: As shown by players H, I and J.
- Goalie: As shown by player K.
Using the picture of a hockey field below, answer the questions that follow:

The coordinates of the centroid of ΔEHJ are ______.
The point P(–2, 4) lies on a circle of radius 6 and centre C(3, 5).
What is the distance of the point (– 5, 4) from the origin?
A point (x, y) is at a distance of 5 units from the origin. How many such points lie in the third quadrant?
