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प्रश्न
If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?
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उत्तर
Consider the points A(4, k) and B(1, 0).
It is given that the distance AB is 5 units.
By distance formula, disance AB is as follows:
`AB = sqrt((4-1)^2 + (k - 0)^2)`
`=> 5 = sqrt(9 + (k)^2)`
`=> 25 = 9 + k^2`
`=> 16 = k^2`
`=> +- 4 = k`
Hence, value of ka are `+- 4`
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