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प्रश्न
Calculate the distance between A (7, 3) and B on the x-axis, whose abscissa is 11.
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उत्तर
Here B is (11, 0)
AB = `sqrt((11 − 7)^2 + (0 − 3)^2)`
= `sqrt((4)^2 + (−3)^2)`
= `sqrt(16 + 9)`
= `sqrt(25)`
= 5 units.
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संबंधित प्रश्न
Find the distance between the following pairs of points:
(a, b), (−a, −b)
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2) Find the coordinates of the point of intersection.
3) The length of AB.
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Find the distance of a point (13 , -9) from another point on the line y = 0 whose abscissa is 1.
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Given A = (3, 1) and B = (0, y - 1). Find y if AB = 5.
Find distance between point A(–3, 4) and origin O.
Find distance between point A(–1, 1) and point B(5, –7):
Solution: Suppose A(x1, y1) and B(x2, y2)
x1 = –1, y1 = 1 and x2 = 5, y2 = –7
Using distance formula,
d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
∴ d(A, B) = `sqrt(square +[(-7) + square]^2`
∴ d(A, B) = `sqrt(square)`
∴ d(A, B) = `square`
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