Advertisements
Advertisements
प्रश्न
Calculate the distance between A (7, 3) and B on the x-axis, whose abscissa is 11.
Advertisements
उत्तर
Here B is (11, 0)
AB = `sqrt((11 − 7)^2 + (0 − 3)^2)`
= `sqrt((4)^2 + (−3)^2)`
= `sqrt(16 + 9)`
= `sqrt(25)`
= 5 units.
APPEARS IN
संबंधित प्रश्न
If A(4, 3), B(-1, y) and C(3, 4) are the vertices of a right triangle ABC, right-angled at A, then find the value of y.
Find the distances between the following point.
A(a, 0), B(0, a)
A(-2, -3), B(-1, 0) and C(7, -6) are the vertices of a triangle. Find the circumcentre and the circumradius of the triangle.
Find the coordinates of the points on the y-axis, which are at a distance of 10 units from the point (-8, 4).
A point P (2, -1) is equidistant from the points (a, 7) and (-3, a). Find a.
The distance between the point P(1, 4) and Q(4, 0) is ______.
The distance of the point (α, β) from the origin is ______.
Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5).
What type of a quadrilateral do the points A(2, –2), B(7, 3), C(11, –1) and D(6, –6) taken in that order, form?
The centre of a circle is (2a, a – 7). Find the values of a if the circle passes through the point (11, – 9) and has diameter `10sqrt(2)` units.
