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प्रश्न
Find the value of y for which the distance between the points A (3, −1) and B (11, y) is 10 units.
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उत्तर
The given points are A (3, −1) and B (11, y).
It is given that AB = 10 units.
`∴ sqrt((11-3)^2+[y-(-1)]^2=10)`
`rArr sqrt(64+(y+1)^2)=100`
`rArr 64+(y+1)^2=100`
`rArr (y+1)^2=100-64=36`
`rArr y+1=+-6`
`rArr y+1=6` or `y+1=-6`
`rArry=6-1=5` or `y=-6-1=-7`
Thus, the value of y is 5 or −7
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