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The Distances of Point P (X, Y) from the Points a (1, -3) and B (-2, 2) Are in the Ratio 2: 3. Show That: 5x2 + 5y2 - 34x + 70y + 58 = 0. - Mathematics

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Question

The distances of point P (x, y) from the points A (1, - 3) and B (- 2, 2) are in the ratio 2: 3.
Show that: 5x2 + 5y2 - 34x + 70y + 58 = 0.

Sum
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Solution

It is given that PA: PB = 2: 3

`"PA"/"PB" = (2)/(3)`

`"PA"^2/"PB"^2 = (4)/(9)`

`((x - 1)^2 + (y + 3)^2)/((x + 2)^2 + (y - 2)^2) = (4)/(9)`

`(x^2 + 1 -2x + y^2 + 9 + 6y)/(x^2 + 4 + 4x + y^2 + 4 - 4y) = (4)/(9)`

9(x2 - 2x + y2 + 10 + 6y) = 4(x2 + 4x + y2 + 8 - 4y)

9x2 - 18x + 9y2 + 90 + 54y = 4x2 + 16x + 4y2 + 32 - 16y

5x2 + 5y2 - 34x + 70y + 58 = 0

Hence, proved.

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Chapter 28: Distance Formula - Exercise 28 [Page 335]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 28 Distance Formula
Exercise 28 | Q 27 | Page 335

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