Advertisements
Advertisements
Question
Find the distance between the origin and the point:
(8, −15)
Advertisements
Solution
Coordinates of origin are O (0, 0).
C (8, −15)
CO = `sqrt((0 - 8)^2 + (0 + 15)^2)`
= `sqrt(64 + 225)`
= `sqrt(289)`
= 17
APPEARS IN
RELATED QUESTIONS
Prove that the points A(1, 7), B (4, 2), C(−1, −1) D (−4, 4) are the vertices of a square.
Using the distance formula, show that the given points are collinear:
(6, 9), (0, 1) and (-6, -7)
Find the distance between the following pair of point.
T(–3, 6), R(9, –10)
Determine whether the point is collinear.
R(0, 3), D(2, 1), S(3, –1)
Find the distance between the following point :
(sec θ , tan θ) and (- tan θ , sec θ)
Prove that the following set of point is collinear :
(4, -5),(1 , 1),(-2 , 7)
Prove that the points (1 ,1),(-4 , 4) and (4 , 6) are the certices of an isosceles triangle.
Find the distance between the origin and the point:
(-8, 6)
Find the distance of the following points from origin.
(a cos θ, a sin θ).
Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).
