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प्रश्न
Find the distance between the origin and the point:
(8, −15)
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उत्तर
Coordinates of origin are O (0, 0).
C (8, −15)
CO = `sqrt((0 - 8)^2 + (0 + 15)^2)`
= `sqrt(64 + 225)`
= `sqrt(289)`
= 17
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संबंधित प्रश्न
Determine if the points (1, 5), (2, 3) and (−2, −11) are collinear.
Find the distance between the following pair of points.
L(5, –8), M(–7, –3)
Find the distance of a point (7 , 5) from another point on the x - axis whose abscissa is -5.
Find the relation between a and b if the point P(a ,b) is equidistant from A (6,-1) and B (5 , 8).
Prove that the following set of point is collinear :
(5 , 5),(3 , 4),(-7 , -1)
Prove that the points (6 , -1) , (5 , 8) and (1 , 3) are the vertices of an isosceles triangle.
ABCD is a square . If the coordinates of A and C are (5 , 4) and (-1 , 6) ; find the coordinates of B and D.
Calculate the distance between A (7, 3) and B on the x-axis whose abscissa is 11.
Show that the point (11, –2) is equidistant from (4, –3) and (6, 3).
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In a GPS, The lines that run east-west are known as lines of latitude, and the lines running north-south are known as lines of longitude. The latitude and the longitude of a place are its coordinates and the distance formula is used to find the distance between two places. The distance between two parallel lines is approximately 150 km. A family from Uttar Pradesh planned a round trip from Lucknow (L) to Puri (P) via Bhuj (B) and Nashik (N) as shown in the given figure below.
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Based on the above information answer the following questions using the coordinate geometry.
- Find the distance between Lucknow (L) to Bhuj (B).
- If Kota (K), internally divide the line segment joining Lucknow (L) to Bhuj (B) into 3 : 2 then find the coordinate of Kota (K).
- Name the type of triangle formed by the places Lucknow (L), Nashik (N) and Puri (P)
[OR]
Find a place (point) on the longitude (y-axis) which is equidistant from the points Lucknow (L) and Puri (P).
