Advertisements
Advertisements
प्रश्न
Find the distance between the origin and the point:
(8, −15)
Advertisements
उत्तर
Coordinates of origin are O (0, 0).
C (8, −15)
CO = `sqrt((0 - 8)^2 + (0 + 15)^2)`
= `sqrt(64 + 225)`
= `sqrt(289)`
= 17
APPEARS IN
संबंधित प्रश्न
If P and Q are two points whose coordinates are (at2 ,2at) and (a/t2 , 2a/t) respectively and S is the point (a, 0). Show that `\frac{1}{SP}+\frac{1}{SQ}` is independent of t.
The length of a line segment is of 10 units and the coordinates of one end-point are (2, -3). If the abscissa of the other end is 10, find the ordinate of the other end.
Using the distance formula, show that the given points are collinear:
(-1, -1), (2, 3) and (8, 11)
Determine whether the points are collinear.
A(1, −3), B(2, −5), C(−4, 7)
Distance of point (−3, 4) from the origin is ______.
If the point P(2, 1) lies on the line segment joining points A(4, 2) and B(8, 4), then ______.
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
By using the distance formula prove that each of the following sets of points are the vertices of a right angled triangle.
(i) (6, 2), (3, -1) and (- 2, 4)
(ii) (-2, 2), (8, -2) and (-4, -3).
Show that the point (0, 9) is equidistant from the points (– 4, 1) and (4, 1)
The distance of the point (α, β) from the origin is ______.
