Advertisements
Advertisements
प्रश्न
The distance between the points (3, 1) and (0, x) is 5. Find x.
Advertisements
उत्तर
It is given that the distance between the points A (3, 1) and B (0, x) is 5.
∴ AB = 5
AB2 = 25
(0 - 3)2 + (x - 1)2 = 25
9 + x2 + 1 - 2x = 25
x2 - 2x - 15 = 0
x2 - 5x + 3x - 15 = 0
x(x - 5) + 3(x - 5) = 0
(x - 5)(x + 3) = 0
x = 5, -3
APPEARS IN
संबंधित प्रश्न
Show that four points (0, – 1), (6, 7), (–2, 3) and (8, 3) are the vertices of a rectangle. Also, find its area
Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer:
(- 1, - 2), (1, 0), (- 1, 2), (- 3, 0)
Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).
Find the distance between the points
A(1,-3) and B(4,-6)
Find the distance between the points:
P(a + b, a - b) and Q(a - b, a + b)
Find the distance between the following pairs of point.
W `((- 7)/2 , 4)`, X (11, 4)
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.
Find the distance of the following points from origin.
(a+b, a-b)
The distance of the point (α, β) from the origin is ______.
Find the points on the x-axis which are at a distance of `2sqrt(5)` from the point (7, – 4). How many such points are there?
