Advertisements
Advertisements
प्रश्न
The distance between the points (3, 1) and (0, x) is 5. Find x.
Advertisements
उत्तर
It is given that the distance between the points A (3, 1) and B (0, x) is 5.
∴ AB = 5
AB2 = 25
(0 - 3)2 + (x - 1)2 = 25
9 + x2 + 1 - 2x = 25
x2 - 2x - 15 = 0
x2 - 5x + 3x - 15 = 0
x(x - 5) + 3(x - 5) = 0
(x - 5)(x + 3) = 0
x = 5, -3
APPEARS IN
संबंधित प्रश्न
If the point P(x, y) is equidistant from the points A(a + b, b – a) and B(a – b, a + b). Prove that bx = ay.
Prove that the points (–3, 0), (1, –3) and (4, 1) are the vertices of an isosceles right angled triangle. Find the area of this triangle
The length of a line segment is of 10 units and the coordinates of one end-point are (2, -3). If the abscissa of the other end is 10, find the ordinate of the other end.
Find the distance between the points
A(-6,-4) and B(9,-12)
Find the value of m if the distance between the points (m , -4) and (3 , 2) is 3`sqrt 5` units.
Show that the points (2, 0), (–2, 0), and (0, 2) are the vertices of a triangle. Also, a state with the reason for the type of triangle.
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.
Find the distance of the following points from origin.
(a+b, a-b)
The point which divides the lines segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the ______.
The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure is ______.

