Advertisements
Advertisements
प्रश्न
The distance between the points (3, 1) and (0, x) is 5. Find x.
Advertisements
उत्तर
It is given that the distance between the points A (3, 1) and B (0, x) is 5.
∴ AB = 5
AB2 = 25
(0 - 3)2 + (x - 1)2 = 25
9 + x2 + 1 - 2x = 25
x2 - 2x - 15 = 0
x2 - 5x + 3x - 15 = 0
x(x - 5) + 3(x - 5) = 0
(x - 5)(x + 3) = 0
x = 5, -3
APPEARS IN
संबंधित प्रश्न
Check whether (5, -2), (6, 4) and (7, -2) are the vertices of an isosceles triangle.
Find the distance between the following point :
(sec θ , tan θ) and (- tan θ , sec θ)
Prove that the following set of point is collinear :
(4, -5),(1 , 1),(-2 , 7)
Find the coordinate of O , the centre of a circle passing through A (8 , 12) , B (11 , 3), and C (0 , 14). Also , find its radius.
Find the coordinate of O , the centre of a circle passing through P (3 , 0), Q (2 , `sqrt 5`) and R (`-2 sqrt 2` , -1). Also find its radius.
Find the distance between the origin and the point:
(-8, 6)
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.
Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.
Show that points A(–1, –1), B(0, 1), C(1, 3) are collinear.
A point (x, y) is at a distance of 5 units from the origin. How many such points lie in the third quadrant?
