Advertisements
Advertisements
प्रश्न
Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.
Advertisements
उत्तर
We know that any point on y-axis has coordinates of the form (0, y).
Ordinate of point B = 9
Since, B lies of y-axis, so its co-ordinates are (0, 9).
AB = `sqrt((0 -5)^2 + (9 + 3)^2)`
= `sqrt(25 + 144)`
= `sqrt(169)`
= 13 units
APPEARS IN
संबंधित प्रश्न
Find the distance between the points
(ii) A(7,-4)and B(-5,1)
Find the distance between the points
P(a sin ∝,a cos ∝ )and Q( acos ∝ ,- asin ∝)
Find the distance of the following points from the origin:
(iii) C (-4,-6)
Determine whether the points are collinear.
A(1, −3), B(2, −5), C(−4, 7)
Find the distances between the following point.
R(–3a, a), S(a, –2a)
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
Prove that the points (0 , 2) , (1 , 1) , (4 , 4) and (3 , 5) are the vertices of a rectangle.
Show that the points P (0, 5), Q (5, 10) and R (6, 3) are the vertices of an isosceles triangle.
The distance of the point (α, β) from the origin is ______.
A circle has its centre at the origin and a point P(5, 0) lies on it. The point Q(6, 8) lies outside the circle.
