Advertisements
Advertisements
प्रश्न
Find the co-ordinates of points on the x-axis which are at a distance of 17 units from the point (11, -8).
Advertisements
उत्तर
Let the coordinates of the point on x-axis be (x, 0).
From the given information, we have:
`sqrt((x -11)^2 + (0 + 8)^2)` = 17
(x - 11)2 + (0 + 8)2 = 289
x2 + 121 - 22x + 64 = 289
x2 - 22x - 104 = 0
x2 - 26x + 4x - 104 = 0
x(x - 26) + 4(x - 26) = 0
(x - 26)(x + 4) = 0
x = 26, -4
Thus, the required co-ordinates of the points on x-axis are (26, 0) and (-4, 0).
APPEARS IN
संबंधित प्रश्न
If the point (x, y) is equidistant from the points (a + b, b – a) and (a – b, a + b), prove that bx = ay.
Find the distance between the points
(i) A(9,3) and B(15,11)
Find the distance between the points
A(-6,-4) and B(9,-12)
Determine whether the points are collinear.
A(1, −3), B(2, −5), C(−4, 7)
Find the coordinate of O , the centre of a circle passing through P (3 , 0), Q (2 , `sqrt 5`) and R (`-2 sqrt 2` , -1). Also find its radius.
Prove that the points (1 , 1) , (-1 , -1) and (`- sqrt 3 , sqrt 3`) are the vertices of an equilateral triangle.
Prove that the points (a, b), (a + 3, b + 4), (a − 1, b + 7) and (a − 4, b + 3) are the vertices of a parallelogram.
Show that the points (2, 0), (–2, 0), and (0, 2) are the vertices of a triangle. Also, a state with the reason for the type of triangle.
Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).
Find a point which is equidistant from the points A(–5, 4) and B(–1, 6)? How many such points are there?
