Advertisements
Advertisements
प्रश्न
Find the distance between the following pairs of points:
(–3, 6) and (2, –6)
Advertisements
उत्तर
(–3, 6) and (2, –6)
x1 = –3, y1 = 6, x2 = 2, y2 = –6
AB = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`
= `sqrt((2 + 3)^2 + (-6 -6)^2)`
= `sqrt((5)^2 + (-12)^2)`
= `sqrt(25 + 144)`
= `sqrt(169)`
= 13
APPEARS IN
संबंधित प्रश्न
Find the coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, – 2) and (2, – 2). Also, find its circum radius
The length of a line segment is of 10 units and the coordinates of one end-point are (2, -3). If the abscissa of the other end is 10, find the ordinate of the other end.
Given a triangle ABC in which A = (4, −4), B = (0, 5) and C = (5, 10). A point P lies on BC such that BP : PC = 3 : 2. Find the length of line segment AP.
Find the value of a if the distance between the points (5 , a) and (1 , 5) is 5 units .
Find the relation between a and b if the point P(a ,b) is equidistant from A (6,-1) and B (5 , 8).
Prove that the following set of point is collinear :
(4, -5),(1 , 1),(-2 , 7)
Prove that the points (0 , -4) , (6 , 2) , (3 , 5) and (-3 , -1) are the vertices of a rectangle.
From the given number line, find d(A, B):
Find the distance between the origin and the point:
(-5, -12)
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the ordinate of point P.
