Advertisements
Advertisements
प्रश्न
Find the distance between the following pairs of points:
(–3, 6) and (2, –6)
Advertisements
उत्तर
(–3, 6) and (2, –6)
x1 = –3, y1 = 6, x2 = 2, y2 = –6
AB = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`
= `sqrt((2 + 3)^2 + (-6 -6)^2)`
= `sqrt((5)^2 + (-12)^2)`
= `sqrt(25 + 144)`
= `sqrt(169)`
= 13
APPEARS IN
संबंधित प्रश्न
Name the type of quadrilateral formed, if any, by the following point, and give reasons for your answer:
(4, 5), (7, 6), (4, 3), (1, 2)
Find the distance between the points:
P(a sin α, a cos α) and Q(a cos α, – a sin α)
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is ______.
Find the distance between the origin and the point:
(-8, 6)
Given A = (x + 2, -2) and B (11, 6). Find x if AB = 17.
The point which divides the lines segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the ______.
The distance between the points A(0, 6) and B(0, –2) is ______.
Points A(4, 3), B(6, 4), C(5, –6) and D(–3, 5) are the vertices of a parallelogram.
If (– 4, 3) and (4, 3) are two vertices of an equilateral triangle, find the coordinates of the third vertex, given that the origin lies in the interior of the triangle.
Find distance between points P(– 5, – 7) and Q(0, 3).
By distance formula,
PQ = `sqrt(square + (y_2 - y_1)^2`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(125)`
= `5sqrt(5)`
