Advertisements
Advertisements
प्रश्न
Show that the points P (0, 5), Q (5, 10) and R (6, 3) are the vertices of an isosceles triangle.
Advertisements
उत्तर
PQ = `sqrt((5 - 0)^2 + (10 - 5)^2`
= `sqrt(25+25)`
= `sqrt(50)`
= 5`sqrt(2)`
QR = `sqrt((6 - 5)^2 + (3 - 10)^2`
= `sqrt(1+49)`
= `sqrt(50)`
= 5`sqrt(2)`
RP = `sqrt((0 - 6)^2 + (5 - 3)^2`
= `sqrt(36+4)`
= `sqrt(40)`
= 2`sqrt(10)`
Since, PQ = QR, ΔPQR is an isosceles triangle.
APPEARS IN
संबंधित प्रश्न
If A(5, 2), B(2, −2) and C(−2, t) are the vertices of a right angled triangle with ∠B = 90°, then find the value of t.
Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (−3, 4).
`" Find the distance between the points" A ((-8)/5,2) and B (2/5,2)`
Find the distance between the following pair of point.
T(–3, 6), R(9, –10)
Show that (-3, 2), (-5, -5), (2, -3) and (4, 4) are the vertices of a rhombus.
The distance between the points A(0, 6) and B(0, -2) is ______.
If the distance between the points (4, P) and (1, 0) is 5, then the value of p is ______.
What type of a quadrilateral do the points A(2, –2), B(7, 3), C(11, –1) and D(6, –6) taken in that order, form?
The point P(–2, 4) lies on a circle of radius 6 and centre C(3, 5).
Read the following passage:
|
Alia and Shagun are friends living on the same street in Patel Nagar. Shagun's house is at the intersection of one street with another street on which there is a library. They both study in the same school and that is not far from Shagun's house. Suppose the school is situated at the point O, i.e., the origin, Alia's house is at A. Shagun's house is at B and library is at C. |
Based on the above information, answer the following questions.
- How far is Alia's house from Shagun's house?
- How far is the library from Shagun's house?
- Show that for Shagun, school is farther compared to Alia's house and library.
OR
Show that Alia’s house, shagun’s house and library for an isosceles right triangle.
