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प्रश्न
A(2, 5), B(-2, 4) and C(-2, 6) are the vertices of a triangle ABC. Prove that ABC is an isosceles triangle.
योग
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उत्तर
AB = `sqrt ((2 + 2)^2 + (5 - 4)^2) = sqrt (16 + 1) = sqrt 17` units
BC = `sqrt ((-2 + 2)^2 + (4 - 6)^2) = sqrt (0 + 4)` = 2 units
AC = `sqrt ((2 + 2)^2 + (5 - 6)^2) = sqrt (16 + 1) = sqrt 17` units
It can be seen that AB = AC
Hence , the given coordinates are the vertices of an isosceles triangle.
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