Advertisements
Advertisements
प्रश्न
Find the value of a, if the distance between the points A(–3, –14) and B(a, –5) is 9 units.
Advertisements
उत्तर
Distance between two points (x1, y1) ( x2, y2) is:
d = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
Distance between A(–3, –14) and B(a, –5) is:
d = `sqrt([(a + 3)^2 + (-5 + 14)^2])` = 9
Squaring on L.H.S and R.H.S.
(a + 3)2 + 81 = 81
(a + 3)2 = 0
(a + 3)(a + 3) = 0
a + 3 = 0
a = –3
APPEARS IN
संबंधित प्रश्न
If the point (x, y) is equidistant from the points (a + b, b – a) and (a – b, a + b), prove that bx = ay
Find the distance of the following points from the origin:
(i) A(5,- 12)
If the point A(x,2) is equidistant form the points B(8,-2) and C(2,-2) , find the value of x. Also, find the value of x . Also, find the length of AB.
Find the distance between the following pair of point.
P(–5, 7), Q(–1, 3)
Determine whether the point is collinear.
R(0, 3), D(2, 1), S(3, –1)
AB and AC are the two chords of a circle whose radius is r. If p and q are
the distance of chord AB and CD, from the centre respectively and if
AB = 2AC then proove that 4q2 = p2 + 3r2.
Find the distance of a point (13 , -9) from another point on the line y = 0 whose abscissa is 1.
Find the relation between x and y if the point M (x,y) is equidistant from R (0,9) and T (14 , 11).
Find the coordinate of O , the centre of a circle passing through A (8 , 12) , B (11 , 3), and C (0 , 14). Also , find its radius.
Prove that the points (6 , -1) , (5 , 8) and (1 , 3) are the vertices of an isosceles triangle.
ABCD is a square . If the coordinates of A and C are (5 , 4) and (-1 , 6) ; find the coordinates of B and D.
Points A (-3, -2), B (-6, a), C (-3, -4) and D (0, -1) are the vertices of quadrilateral ABCD; find a if 'a' is negative and AB = CD.
The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x ______
The point which lies on the perpendicular bisector of the line segment joining the points A(–2, –5) and B(2, 5) is ______.
A circle drawn with origin as the centre passes through `(13/2, 0)`. The point which does not lie in the interior of the circle is ______.
The equation of the perpendicular bisector of line segment joining points A(4,5) and B(-2,3) is ______.
∆ABC with vertices A(–2, 0), B(2, 0) and C(0, 2) is similar to ∆DEF with vertices D(–4, 0), E(4, 0) and F(0, 4).
Points A(4, 3), B(6, 4), C(5, –6) and D(–3, 5) are the vertices of a parallelogram.
Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5).
What is the distance of the point (– 5, 4) from the origin?
