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Find x if distance between points L(x, 7) and M(1, 15) is 10.

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प्रश्न

Find x if distance between points L(x, 7) and M(1, 15) is 10. 

योग
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उत्तर १

L(x, 7), M(1, 15), and LM = 10.

By distance formula,

∴ LM = `sqrt((x − 1)^2 + (7 − 15)^2)`

∴ 10 = `sqrt((x - 1)^2 + (− 8)^2)`

Squaring both the sides, we get,

∴ 100 = (x − 1)2 + 64

∴ (x − 1)2 = 100 − 64

∴ (x − 1)2 = 36

Taking square roots of both the sides,

∴ x − 1 = `+-` 6

∴ x − 1 = 6        or        x - 1 = −6

∴ x = 6 + 1       or        x = −6 + 1

∴ x = 7       or        x = −5

x = 7 or x = −5

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उत्तर २

L(x, 7), M(1, 15), and LM = 10.

By distance formula,

∴ LM = `sqrt((x − 1)^2 + (7 − 15)^2)`

∴ 10 = `sqrt((x - 1)^2 + (− 8)^2)`

Squaring both the sides, we get,

∴ 100 = (x − 1)2 + 64

∴ 100 = x2 − 2x + 1 + 64

∴ 100 = x2 − 2x + 65

∴ x2 − 2x + 65 − 100 = 0

∴ x2 − 2x − 35 = 0

∴ x2 − 7x + 5x - 35 = 0

∴ x(x − 7) + 5(x − 7) = 0

∴ (x − 7)(x + 5) = 0

∴ x − 7  = 0          or       x + 5 = 0  

∴ x = 7          or             x = −5

x = 7 or x = −5

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Co-ordinate Geometry - Practice Set 5.1 [पृष्ठ १०८]

APPEARS IN

बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 5 Co-ordinate Geometry
Practice Set 5.1 | Q 7 | पृष्ठ १०८

संबंधित प्रश्न

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The value of 'a' for which of the following points A(a, 3), B (2, 1) and C(5, a) a collinear. Hence find the equation of the line.


Find the circumcenter of the triangle whose vertices are (–2, –3), (–1, 0), (7, –6).


Find the distance between the following pair of point.

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A(a, 0), B(0, a)


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(4 , 1) and (-4 , 5)


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The length of line PQ is 10 units and the co-ordinates of P are (2, -3); calculate the co-ordinates of point Q, if its abscissa is 10.


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(a cos θ, a sin θ).


KM is a straight line of 13 units If K has the coordinate (2, 5) and M has the coordinates (x, – 7) find the possible value of x.


Find distance between point Q(3, –7) and point R(3, 3)

Solution: Suppose Q(x1, y1) and point R(x2, y2)

x1 = 3, y1 = –7 and x2 = 3, y2 = 3

Using distance formula,

d(Q, R) = `sqrt(square)`

∴ d(Q, R) = `sqrt(square - 100)`

∴ d(Q, R) =  `sqrt(square)`

∴ d(Q, R) = `square`


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Solution: Suppose A(x1, y1) and B(x2, y2)

x1 = –1, y1 = 1 and x2 = 5, y2 = –7

Using distance formula,

d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

∴ d(A, B) = `sqrt(square +[(-7) + square]^2`

∴ d(A, B) = `sqrt(square)`

∴ d(A, B) = `square`


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Read the following passage:

Use of mobile screen for long hours makes your eye sight weak and give you headaches. Children who are addicted to play "PUBG" can get easily stressed out. To raise social awareness about ill effects of playing PUBG, a school decided to start 'BAN PUBG' campaign, in which students are asked to prepare campaign board in the shape of a rectangle: One such campaign board made by class X student of the school is shown in the figure.

Based on the above information, answer the following questions:

  1. Find the coordinates of the point of intersection of diagonals AC and BD.
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    2. Find the ratio of the length of side AB to the length of the diagonal AC.

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